1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
34kurt
3 years ago
13

Average acceleration of an object is the:

Physics
1 answer:
Andreyy893 years ago
8 0

Answer:

Change in its velocity divided by the change in time

Explanation:

the equation for average acceleration (a) = (vf-vi)/t

a = (velocity final - velocity initial) / change in time

You might be interested in
11.
jolli1 [7]
<h3>Reducing Surface Area.</h3>

If the surface area becomes smaller, the pressure becomes larger.

8 0
3 years ago
Please help I will mark you brainliest
Radda [10]

I believe the answer is a

7 0
3 years ago
Read 2 more answers
Q 2 Two mirrors meet at right angles. A ray of light is incident on one at an angle of 30°
serg [7]

a ray of light is incident towards a plane mirror at an angles of 30degrees with the mirror surface. what will be the angles of reflection is 60degree.

3 0
3 years ago
How many protons does Silicone have<br><br> A.2<br> B.14<br> C.28<br> D.28.08
taurus [48]

Answer:

14

Explanation:

the left top is protons

hope this helps :)

3 0
3 years ago
A 1090 kg car has four 12.7 kg wheels. When the car is moving, what fraction of the total kinetic energy of the car is due to ro
max2010maxim [7]

Answer:

\frac{KE_{Rotational}}{KE_{Total}} = 0.018

Explanation:

To develop this exercise we proceed to use the kinetic energy equations,

In the end we replace

KE_{Total}=KE_{Translational}+KE_{Rotational}

KE_{Total}=\frac{1}{2}m_{car}+4*\frac{1}{2}*I*(\frac{v}{r})^2

Here

I=\frac{1}{2}m_{wheels}*r^2 meaning the 4 wheels,

So replacing

KE_{Rotational}=4\frac{1}{2}*(\frac{1}{2}m_{wheels}*r^2)*(\frac{v}{r})^2=m*v^2

So,

\frac{KE_{Rotational}}{KE_{Total}} = \frac{m_{wheels}*v^2}{\frac{1}{2}m_{car}*v^2+m_{wheels}*v^2}

\frac{KE_{Rotational}}{KE_{Total}} = \frac{m_{wheels}}{\frac{1}{2}m_{car}+m_{wheels}}

\frac{KE_{Rotational}}{KE_{Total}} =  \frac{10}{545+10}

\frac{KE_{Rotational}}{KE_{Total}} = 0.018

3 0
3 years ago
Other questions:
  • A slender, uniform metal rod of mass M and length lis pivoted without friction about an axis through its midpoint andperpendicul
    13·2 answers
  • Is it possible for several scientists who have never met each other to contribute to the same scientific knowledge, theory, or l
    6·2 answers
  • Gold has a specific heat of 0.130 J/g*C. If 195 joules of heat are added to 15 grams of gold how much does the temperature of th
    7·1 answer
  • 17. A 25 kg block is initially at rest on a rough, horizontal surface. A horizontal force of 75 N is required to set
    13·1 answer
  • Define Velocity.<br>Have a Nice Day Ahead​
    5·1 answer
  • HELP ME ASAP!!!! PIC IS DOWN BELOW!
    8·2 answers
  • A horizontal force of 30N is applied to a mass of 10 kg causing it to accelerate. If the coefficient of friction is 0.20 what is
    8·1 answer
  • A successful marriage is based on:
    14·2 answers
  • WhT is marasmus my followers and following pls give answer in detail ​
    12·2 answers
  • Can anyone follow me​
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!