Answer: The density of 0.50 grams of gaseous carbon stored under 1.50 atm of pressure at a temperature of -20.0 °C is 0.867 g/L.
Explanation:
- d = m/V, where d is the density, m is the mass and V is the volume.
- We have the mass m = 0.50 g, so we must get the volume V.
- To get the volume of a gas, we apply the general gas law PV = nRT
P is the pressure in atm (P = 1.5 atm)
V is the volume in L (V = ??? L)
n is the number of moles in mole, n = m/Atomic mass, n = 0.50/12.0 = 0.416 mole.
R is the general gas constant (R = 0.082 L.atm/mol.K).
T is the temperature in K (T(K) = T(°C) + 273 = -20.0 + 273 = 253 K).
- Then, V = nRT/P = (0.416 mol)(0.082 L.atm/mol.K)(253 K) / (1.5 atm) = 0.576 L.
- Now, we can obtain the density; d = m/V = (0.50 g) / (0.576 L) = 0.867 g/L.
1 mole has 6.02*10^23 molecules in it.
1 nickel (II) chloride molecule, NiCl2, has 1 Ni atom in it.
so 1 mole of nickel (II) chloride molecule has 1 mole of Ni atom in it.
so 100 moles of nickel (II) chloride molecule has 100*6.02*10^23
= 6.02*10^25 Ni atom in it.
Using ideal gas equation, PV = nRT, and since there is no volume change and amount change, the equation is now P = kT, where k =nR/V. Temperature must be in kelvin
From the given, k = (0.82)/ (21 + 273) = 2.78 x 10^-3
Substituting T = -3.5+273, P = 0.75 atm
Answer:
not sure o. increasing pressure and decreasing temperature
Assuming ideal gases, and that there is no volume variation,
And use the temperature transformation from Celsius to Kelvin.
