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kumpel [21]
3 years ago
12

What is the broadest, most general level of taxonomy?

Chemistry
1 answer:
nikdorinn [45]3 years ago
8 0

Answer:The levels of classification are as follows (Broadest to

narrowest): Domain, Kingdom, Phylum, Class, Order, Family, Genus,

Species

Explanation:

You might be interested in
I really need help with this assignment
Mumz [18]

Answer:

A. Sublimation of camphor

8 0
3 years ago
1. write the complete chemical symbol for the ion with 14 protons 15 neutrons and 18 electrons
motikmotik

Answer:

1.   Si^{-4}

2.  Co^{+2}

Explanation:

An ion is formed when an atom that is said to be neutral gains or losses electrons.

It is thought that a negative ion (anion) is produced as it gains electrons and a positive ion (cation) is formed when it loses an electron.

Atomic number is the total number of protons and electrons in a neutral atom.

From the information

Protons = 14

electron = 18

Net Charge = no of proton - no of electron

= 14 - 18 = -4

Mass number = 14 + 15 = 29

Thus, the chemical symbol = Si^{-4}

For ion with 27 proton, 32 neutrons and 25 electrons

Net charge = 27 - 25 = +2

Mass number = 27 + 32 = 59

Thus, the chemical symbol = Co^{+2}

6 0
3 years ago
Write the symbol for every chemical element that has an atomic number less than 13 and atomic mass greater than 19.3 u
emmainna [20.7K]

Answer:

The symbol of each element is, Ne, Na, Mg, and Al.

Explanation:

Below is the list of elements that has an atomic mass of less than 19.3 u.

The atomic mass of Neon is 20.1797 u and the atomic number is 10.

The atomic mass of Sodium is 22.989769 u and the atomic number is 11.

The atomic mass of Magnesium is 24.305 u and the atomic number is 12.

The atomic mass of Aluminium is 26.981539 u and the atomic number is 13.

Here, the symbol of each element is, Ne, Na, Mg, and Al.

3 0
3 years ago
Why did a drop of water need to be added in order to initiate the reaction?
jeka57 [31]

D.because the water is needed to wet the sand and keep the reaction safe

5 0
3 years ago
Read 2 more answers
You are asked to prepare 500. mL 0.150 M acetate buffer at pH 5.10 using only pure acetic acid ( MW = 60.05 g/mol, p K a = 4.76
Amanda [17]

Answer:

4.504g of acetic acid

Explanation:

The acetic acid in reaction with NaOH produce acetate ion, thus:

CH₃COOH + NaOH → CH₃COO⁻ + H₂O + Na⁺

<em>That means the moles of acetate buffer comes, in the first, from the acetic acid</em>

As you need 500mL (0,500L) of a 0.150M acetate buffer, moles are:

0.500L × (0.150mol / 1L) = <em>0.075 moles of acetate</em>. That is:

0.075mol = [CH₃COO⁻] + [CH₃COOH]

Thus, grams of acetic acid you need to prepare the buffer are:

0.075 moles acetic acid × (60.05g / 1mol) = <em>4.504g of acetic acid</em>

6 0
4 years ago
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