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V125BC [204]
1 year ago
7

A plane electromagnetic wave of frequency 20 GHz moves in the positive y-axis direction such that its electric field is pointed

along the z-axis. The amplitude of the electric field is 10 V/m. The start of time is chosen so that at t
Physics
1 answer:
gulaghasi [49]1 year ago
5 0

A plane electromagnetic wave of frequency 20 GHz moves in the positive y-axis direction such that its electric field is pointed along the z-axis. The amplitude of the electric field is 10 V/m. The start of time is chosen so that at t

When an electric field interacts with a magnetic field, electromagnetic waves are created. Therefore, they are referred to as "electromagnetic" waves. An electromagnetic wave's electric field and magnetic field are perpendicular to one another (at right angles).

An electromagnetic spectrum is a group of waves with similar characteristics to electromagnetic waves. All electromagnetic waves are transverse waves, capable of moving through a vacuum, and moving at the same speed in a vacuum, which is 300,000,000 times the speed of light.

To learn more about electromagnetic waves please visit
brainly.com/question/3101711
#SPJ4

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A car with a mass of 600 kg is traveling at a velocity of 10 m/s. How much kinetic energy does it have?
vaieri [72.5K]

Answer:

30000 J = 30 kJ

Explanation:

Kinetic energy is the energy possessed by a moving object solely due to its motion.

You can get the K.E. of an object using the equation,

K.E. = \frac{1}{2} mv^{2}

So you get,

K.E. = \frac{1}{2} 600×10^{2}

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4 years ago
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3 years ago
In a thin film experiment, a wedge of air is used between two glass plates. If the wavelength of the incident light in air is 48
cluponka [151]

Answer:

The thickness is  \Delta y =  2.4 *10^{-6} \  m

Explanation:

From the question we are told that

   The wavelength is  \lambda  = 480 \ nm = 480*10^{-9} \  m

    The first order of the dark  fringe is  m_1 =  16

     The second order of dark fringe considered is  m_2 = 6

Generally the condition for destructive interference is mathematically represented as

        y = \frac{m \lambda}{2}

Here y is the path difference between the central maxima(i.e the origin) and any dark fringe

So  the path difference between the 16th dark fringe and the 6th dark fringe is mathematically represented as

      y_1 - y_2 = \Delta y =  \frac{m_1 \lambda}{2} -  \frac{m_2 \lambda}{2}

=>  y_1 - y_2 = \Delta y =  \frac{16 *480*10^{-9}}{2} -  \frac{6 *480*10^{-9}}{2}

=>  y_1 - y_2 = \Delta y =  5 (480*10^{-9})

=>  \Delta y =  2.4 *10^{-6} \  m

8 0
3 years ago
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