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hammer [34]
3 years ago
11

Can we call Earth as a Satellite? Why?

Physics
1 answer:
never [62]3 years ago
5 0

Answer:

I don't know sorry

Explanation:

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Does peer pressure affect your physical activity routine? Describe this peer pressure and tell whether it is positive or negativ
Alexxx [7]
Yes, peer pressure affects one's physical activity routine. It can do so both negatively and positively. For instance, if one is pressured to do drugs when around their peers, it would most likely lead to an addiction that lasts even when they are not with those people anymore. However, from a positive viewpoint, one's peers could also pressure them to do something productive, such as trying a new beneficial activity that they are afraid of (ex. trying out for a talent show.) This could lead to a disruption in routine as that individual would begin practicing for said talent show. Hence, peer pressure can be both negative and positive, but in both instances, it changes the routine of the individual effected. 
4 0
3 years ago
Read 2 more answers
The near point of an eye is 48.5 cm. A corrective lens is to be used to allow this eye to focus clearly on objects at the distan
Masteriza [31]

Answer:

The focal length of the lens should be -51.5 cm (a concave lens).

Explanation:

The purpose of the lens is to make objects at 48.5 cm appear at the healthy near point. The healthy near point is 25.0 cm.

We use the lens formula

\dfrac{1}{f} = \dfrac{1}{u} + \dfrac{1}{v}

where <em>f</em> = focal length, <em>u</em> = object distance and <em>v</em> = image distance.

In this case, <em>u</em> = 48.5 cm and <em>v</em> = -25.0 cm.

<em>v</em> is negative because the image is virtual an not real. (Here, we are using the real-is-positive sign convention)

\dfrac{1}{f} = \dfrac{1}{48.5} + \dfrac{1}{-25.0} = -\dfrac{23.5}{1212.5}

f = -51.5

The negative sign indicates the lens is concave.

3 0
3 years ago
If an acid is splashed on your skin , wash at once with
Blizzard [7]

water, if this were to occur u would want to immediately wash it with well water.


Reason: Strong bases react with the oils in your skin to produce a soapy feeling layer. Rinse until well after that feeling is gone.

6 0
3 years ago
Question 17 A sample of iron is put into a calorimeter (see sketch at right) that contains of water. The iron sample starts off
ivanzaharov [21]

Complete Question:

A 59.1 g sample of iron is put into a calorimeter (see sketch attached) that contains 100.0 g of water. The iron sample starts off at 85.0 °C and the temperature of the water starts off at 23.0 °C. When the temperature of the water stops changing it's 27.6 °C. The pressure remains constant at 1 atm.

Calculate the specific heat capacity of iron according to this experiment. Be sure your answer is rounded to the correct number of significant digits

(Question attached)

Answer:

c_{iron}=0.568 J/kg.\°C

c_{iron}=0.6 J/kg.\°C (rounded to 1 decimal place)

Explanation:

A calorimeter is used to measure the heat of chemical or physical reactions. The example given in the question is using the calorimeter to determine the specific heat capacity of iron.

When the system reaches equilibrium the iron and water will be the same temperature, T_{e}. The energy lost from the iron will be equal to the energy gained by the water. It is assumed that the only heat exchange is between the iron and water and no exchange with the surroundings.

Q=mc(T_{e}-T_{initial}) (Eq 1)

-Q_{iron}=Q_{water} (Eq 2)

Water:

m_{water}=100.0 g, c_{water}=4.186 J/kg.\°C, T_{initial,water}=23 \°C, T_{e}=27.6 \°C

Iron:

m_{iron}=59.1 g, c_{iron} = ? J/kg.\°C, T_{initial,iron}=85 \°C, T_{e}=27.6 \°C

Substituting Eq 1 into Eq 2 and details extracted from the question:

-m_{iron}c_{iron}(T_{iron,e}-T_{initial})=m_{water}c_{water}(T_{water,e}-T_{initial})

-59.1*c_{iron}(27.6-85)=100.0*4.186(27.6-23)

c_{iron}=0.568 J/kg.\°C

c_{iron}=0.6 J/kg.\°C

4 0
3 years ago
A simple pendulum takes 128s to complete 40 oscillations what is the time period of the pendulum
Serhud [2]

Explanation:

Parameters

Number of oscillation = 40 oscillations

Time of oscillation = 128s

Formular

Period (T) = <u>No of oscillation</u>

Time taken

T = <u>128</u>

40

T=3.2s

3 0
3 years ago
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