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elena-s [515]
1 year ago
12

A substance intentionally added that affects the nature and quality of food is called.

Chemistry
1 answer:
VashaNatasha [74]1 year ago
6 0

A substance intentionally added that affects the nature and quality of food is called food material.

There are seven most important components in food materials: carbohydrates, fats, proteins, vitamins, mineral salts, water and fibre.

Some other examples of food material:

1) Food dyes are chemical substances who gives artificial color to the food.

It is important to know which food dyes are in food because some dyes can cause allergic reactions or cancer.

2) Emulgators are used as an additive to food to emulsify some food.

Emulsions are two or more liquids that are normally not mixable. For example egg yolk and mayonnaise.

More about food dyes: brainly.com/question/23516560

#SPJ4

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Can I mix a sunlight body wash soap and a lemon to get rid of dark spots?​
yuradex [85]

Answer:

Mix ½ teaspoon apple cider vinegar, ½ teaspoon lemon juice, and 1 tablespoon water, and dip a cotton ball in the liquid. Apply to dark

6 0
3 years ago
If 27.3% of a sample of silver-112 decays in 1.52 hours, what is the half-life (in hours to 3 decimal places)?
ICE Princess25 [194]

<u>Answer:</u> The half life of the sample of silver-112 is 3.303 hours.

<u>Explanation:</u>

All radioactive decay processes undergoes first order reaction.

To calculate the rate constant for first order reaction, we use the integrated rate law equation for first order, which is:

k=\frac{2.303}{t}\log \frac{[A_o]}{[A]}

where,

k = rate constant = ?

t = time taken = 1.52 hrs

[A_o] = Initial concentration of reactant = 100 g

[A] = Concentration of reactant left after time 't' = [100 - 27.3] = 72.7 g

Putting values in above equation, we get:

k=\frac{2.303}{1.52hrs}\log \frac{100}{72.7}\\\\k= 0.2098hr^{-1}

To calculate the half life period of first order reaction, we use the equation:

t_{1/2}=\frac{0.693}{k}

where,

t_{1/2} = half life period of first order reaction = ?

k = rate constant = 0.2098hr^{-1}

Putting values in above equation, we get:

t_{1/2}=\frac{0.693}{0.2098hr^{-1}}\\\\t_{1/2}=3.303hrs

Hence, the half life of the sample of silver-112 is 3.303 hours.

6 0
3 years ago
Consider the following statements.
Vsevolod [243]

Answer: B and C only

Explanation:

3 0
3 years ago
Carbon diselenide (CSe2) is a liquid at room temperature. The normal boiling point is 125°C, and the melting point is –45.5°C. C
Tema [17]

Answer:

Explanation:  The strengths of the inter molecular forces varies as follows -

        CO_{2}< CS_{2} < CSe_{2}

The normal boiling point of CSe2 is 125°C and that of CS2 is 116°C, which explains the trend that as we move down the group, the boiling point of e compound increases as the size increases.

This usually happens because larger and heavier atoms have a tendency to exhibit greater inter molecular strengths due to the increase in size . As the size increases, the valence shell electrons move far away from the nucleus, thus has a greater tendency to attract the temporary dipoles.

And larger the inter molecular forces, more tightly the electrons will be held to each other and thus more thermal energy would be required to break the bonds between them.

5 0
3 years ago
How does a catalyst speed up a chemical reaction
ser-zykov [4K]
By being an alternative route to the reaction with a lower activation energy.
5 0
3 years ago
Read 2 more answers
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