Answer: 5289 joules
Explanation:
The quantity of Heat Energy (Q) required to heat a substance depends on its Mass (M), specific heat capacity (C) and change in temperature (Φ)
Thus, Q = MCΦ
Since, Mass of ice = 20 g
C is not provided (Recall that the specific heat capacity of ice is 2.010J/g°C)
Φ = (Final temperature - Initial temperature)
(120°C - (-25°C) =
120°C + 25°C = 145°C
Thus, Q = 20g x 2.010J/g°C x 145°C
Q= 5829J
Thus, 5829Joules of heat energy is required to heat ice
the object's speed and centripetal acceleration in a circle with a constant radius is the exponential curve going up.
acceleration is the rate of change in both speed and direction of velocity over time. When something moves faster or slower in a straight line, it is said to have been accelerated. Because the direction is constantly shifting, motion on a circle accelerates even when the speed is constant. Both effects add to the acceleration for all other types of motion.
It is a vector quantity because acceleration has both a magnitude and a direction. Another vector quantity is velocity. The velocity vector change over a given period of time, divided by that period of time, is the definition of acceleration. The upper limit of the ratio of velocity change provides instantaneous acceleration (at a specific time and place).
Learn more about acceleration here:
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Aerobie. Frisbee. Discus. Javelin. I suppose an American football to some extent.
<span>Pull! Clay pigeons. Arrows. Wingsuit. Kites. Hang gliders. Sails. sailboat keels/dagger boards. Water skis. Ski jumping skis. Boomerang. </span>
<span>I'm excluding spheres and parachutes as bluff bodies even though aerodynamics often plays a big part in their motion.</span>
Answer:Uniform between the plates
Explanation:
Electric Field due to infinite sheet with uniform charge is given by

Where
=charge density
=Space Permittivity
From the formula we can see that Electric field is independent of distance of the particle, so it is uniform between the plates .
I'm not sure but I had this question on a benchmark I think its the density of the wire you need to find the density or the mass I'm not sure but i do remember this question