Answer:
<em><u>Two small metallic spheres with equal mass are suspended as pendulums by strings of length L. The sphereshave the same electric charge and come to equilibrium with each string at an angle of Θ = 10.00° with the vertical. What happens if the electric charges are decreased?</u></em><em><u>(</u></em><em><u>D</u></em><em><u>)</u></em>
Explanation:
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Answer:
0.8c and -0.14c
Explanation:
The first fragment will have a speed of +0.5c respect of a frame of reference moving at +0.5c
Lest name v the velocity of the frame of reference, and u' the velocity of the object respect of this moving frame of reference.
The Lorentz transform for velocity is:
u = (u' + v) / (1 + (u' * v) / c^2)
u = (0.5c + 0.5c) / (1 + (0.5c * 0.5c) / c^2) = 0.8c
The other fragment has a velocity of u' = -0.6c respect of the moving frame of reference.
u = (-0.6v + 0.5c) / (1 + (0.5c * 0.5c) / c^2) = -0.14c
Answer: 9000 kgm/s
Explanation:
Mass of car = 1500 kg
Speed by which car moves = 6 m/s. Momentum of the car = ?
Recall that:
Linear momentum = Mass x Speed
= 1500kg x 6m/s
= 9000 kgm/s
Thus, the linear momentum of the car is 9000 kgm/s