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Aleksandr [31]
3 years ago
14

HELP ME PLEASE- 8th grade science

Chemistry
2 answers:
ale4655 [162]3 years ago
7 0

Answer:

F - Chemical Energy

Explanation:

meriva3 years ago
5 0

Answer: chemical energy

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The atomic weight of iodine is less than the atomic weight of tellurium. However, Mendeleev listed iodine after tellurium in his
QveST [7]

Explanation :

As we know that Mendeleev arranged the elements in horizontal rows and vertical columns of a table in order of their increasing relative atomic weights.

He placed the elements with similar nature in the same group.

According to the question, the atomic weight of iodine is less than the atomic weight of tellurium. So according to this, iodine should be placed before tellurium in Mendeleev's tables. But Mendeleev placed iodine after tellurium in his original periodic table.

However, iodine has similar chemical properties to chlorine and bromine. So, in order to make iodine queue up with chlorine and bromine in his periodic table, Mendeleev exchanged the positions of iodine and tellurium.

As we know that the positions of iodine and tellurium were reversed in Mendeleev's table because iodine has one naturally occurring isotope that is iodine-127  and tellurium isotopes are tellurium-128 and tellurium-130.

Due to high relative abundance of tellurium isotopes gives tellurium the greater relative atomic mass.

3 0
3 years ago
A student conducts an experiment to determine how the addition of salt to water affects the density of the water. The student fi
Alina [70]
3) The density of the water depends on the amount of salt on the water, therefore it is the
dependent variable
8 0
3 years ago
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Calculate the solubility product constant, Ksp, of lead(II) chloride, PbCl2, which has a
V125BC [204]

Answer:

0.0159m

Explanation:

9 M

Explanation:

Lead(II) chloride,  

PbCl

2

, is an insoluble ionic compound, which means that it does not dissociate completely in lead(II) cations and chloride anions when placed in aqueous solution.

Instead of dissociating completely, an equilibrium rection governed by the solubility product constant,  

K

sp

, will be established between the solid lead(II) chloride and the dissolved ions.

PbCl

2(s]

⇌

Pb

2

+

(aq]

+

2

Cl

−

(aq]

Now, the molar solubility of the compound,  

s

, represents the number of moles of lead(II) chloride that will dissolve in aqueous solution at a particular temperature.

Notice that every mole of lead(II) chloride will produce  

1

mole of lead(II) cations and  

2

moles of chloride anions. Use an ICE table to find the molar solubility of the solid

 

PbCl

2(s]

 

⇌

 

Pb

2

+

(aq]

 

+

 

2

Cl

−

(aq]

I

 

 

 

−

 

 

 

 

 

0

 

 

 

 

 

0

C

 

 

x

−

 

 

 

 

(+s)

 

 

 

 

(

+

2

s

)

E

 

 

x

−

 

 

 

 

 

s

 

 

 

 

 

2

s

By definition, the solubility product constant will be equal to

K

sp

=

[

Pb

2

+

]

⋅

[

Cl

−

]

2

K

sp

=

s

⋅

(

2

s

)

2

=

s

3

This means that the molar solubility of lead(II) chloride will be

4

s

3

=

1.6

⋅

10

−

5

⇒

s

=  √ 1.6 4 ⋅ 10 − 5  = 0.0159 M

8 0
3 years ago
Which conclusion is best supported by Julie’s observations?
nirvana33 [79]
Its d beacuse its  the only true statement abot the liquads lol
4 0
3 years ago
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You will first investigate 5 diatomic molecules. Diatomic molecules are made up of 2 atoms.
GenaCL600 [577]

Answer:

Here's what I get  

Explanation:

1. Fluorine

a. Each fluorine atom has seven valence electrons.

b. Fluorine is a nonmetal.

c. The combination of these atoms creates a covalent bond.

d. The atoms share a pair of valence electrons.  

e. In the ionic bond, an electron moved from one atom to the other one.

f. The molecule forms a straight line.

2. Oxygen

a. Each oxygen atom has six valence electrons.

b. Oxygen is a nonmetal.

c. The combination of these atoms creates a covalent bond.

d. The atoms share two pairs of valence electrons.  

e. The bond has four electrons instead of two.

f. The molecule forms a straight line.

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3 years ago
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