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Serjik [45]
3 years ago
5

5.05 g Express your answer as an integer.

Chemistry
1 answer:
Jet001 [13]3 years ago
8 0

Answer:5.5

Explanation:

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P4O10(s) = -3110 kJ/mol H2O(l) = -286 kJ/mol H3PO4(s) = -1279 kJ/mol Calculate the change in enthalpy for the following process:
mash [69]

Answer:

-290KJ/mol

Explanation:

ΔHrxn = ΔHproduct - ΔHreactant

ΔHrxn= 4ΔHH3PO4 - {6ΔHH2O + ΔHP4O10}

ΔHrxn = 4(-1279) - [6(-286) - 3110]

= -5116 -(-1716-3110)

= -5116-(-4826)

= -5116 + 4826 = -290KJ/mol

6 0
2 years ago
The student wants to test the conductivity of each solution. Prior to carrying out the investigation, the student needs to ident
puteri [66]

Answer:b

Explanation: the particles will soon dissolve which means that the particles are changing but the volume is staying the same and the concentration is changing

3 0
2 years ago
Read 2 more answers
Some safety precautions people should take when using fireworks
Lilit [14]

Answer:

Do not try to re-light or handle malfunctioning fireworks. Soak both spent and unused fireworks in water for a few hours before discarding.

3 0
3 years ago
So im confused i don't know what im supposed to do here
FromTheMoon [43]

So I believe you are supposed to take notes based on the guiding questions (the questions on the side).

3 0
3 years ago
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Enter the balanced NET IONIC equation for the potentially unbalanced equation AgNO3(aq)+NaCl(aq)→AgCl(s)+NaNO3(aq).
Zigmanuir [339]

Answer:

Ag^+(aq)+Cl^-(aq)\rightarrow AgCl(s)

Explanation:

Hello!

In this case, since the net ionic equations are ionic representations of the molecular equation in which the spectator ions (those at both reactants and products sides) are cancelled out, we first write the complete ionic equation for this reaction, considering that the solid silver chloride is not ionized due to its precipitation:

Ag^+(aq)+NO_3^-(aq)+Na^+(aq)+Cl^-(aq)\rightarrow AgCl(s)+Na^+(aq)+NO_3^-(aq)

Whereas the nitrate and sodium ions are cancelled out for the aforementioned reason as they are the spectator ions, to obtain:

Ag^+(aq)+Cl^-(aq)\rightarrow AgCl(s)

Which is the required net ionic equation.

Best regards!

4 0
2 years ago
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