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mr_godi [17]
4 years ago
11

Alkaline earth metals electronegativity

Chemistry
1 answer:
Alex4 years ago
7 0

It is usually measured on the Pauling scale, on which the most electronegative element (fluorine) is assigned an electronegativity of 4.0. Each of these elements has a low electronegativity on the Pauling scale, and the electronegativities clearly decrease down the group.

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a 100g sample of material requires 5104.5 joules of heat energy to raise its temperature from 20 degrees Celsius to 80 degrees C
levacccp [35]

Answer: 0.85075J/g.K

Explanation:

Mass of the material = 100g

Energy (Q) = 5104.5J

T1 = 20°C = 293K

T2 = 80°C = 353K

Formula for heat energy (Q) = mc ∇T

Q = mc∇T

∇T = T2 - T1

∇T = 353K - 293K = 60K

Q = mc∇T

C = Q / m∇T

C = (5104.5) / (100 * 60)

C = 0.85075 J/gK

The specific heat capacity of the material is 0.85075J/gK.

5 0
4 years ago
Read 2 more answers
2H2 + O2 = 2H2O is a neutralization or non-neutralization reaction? And explain why..
Gemiola [76]
This is a neutralization reaction since, the hydrogen ion, H+, from the HCl is neutralized by the hydroxide ion, OH-, from the KOH to form the water molecule, H2O and salt, KCl only.
6 0
3 years ago
2. Hydrogen gas at a temperature of 22.0°C that is confined in a 5.00L cylinder exerts a pressure of 4.20atm. If the gas is rele
Umnica [9.8K]

Answer: n∗R=22+273.15/4.2∗5n

P2=n∗R∗T2/V2=n∗R∗33.6+273.15/10

Explanation:

4 0
3 years ago
An element has an average atomic mass of 1.008 amu. It consists of two isotopes , one having a mass of 1.007 amu, and one having
dimulka [17.4K]

Answer:

The most abundant isotope is 1.007 amu.

Explanation:

Given data:

Average atomic mass = 1.008 amu

Mass of first isotope = 1.007 amu

Mass of 2nd isotope = 2.014 amu

Most abundant isotope = ?

Solution:

First of all we will set the fraction for both isotopes

X for the isotopes having mass  2.014 amu

1-x for isotopes having mass 1.007 amu

The average atomic mass is 1.008 amu

we will use the following equation,

2.014x + 1.007  (1-x) = 1.008  

2.014x + 1.007  - 1.007 x = 1.008  

2.014x - 1.007x  =  1.008  -  1.007

1.007 x = 0.001

x= 0.001/ 1.007

x= 0.0009

0.0009 × 100 = 0.09 %

0.09 % is abundance of isotope having mass  2.014 amu because we solve the fraction x.

now we will calculate the abundance of second isotope.

(1-x)

1-0.0009 = 0.9991

0.9991 × 100= 99.91%

6 0
3 years ago
3. A light bulb containing argon gas is switched on,
Readme [11.4K]

Answer:

The assumption is quite reasonable.........

A lightbulb contains Ar gas at a temperature of 295K and at a pressure of 75kPa. The light bulb is switched on, and after 30 minutes its temperature is 418 K. What is a numerical setup for calculating the pressure of the gas inside the light bulb at 418K?

Explanation:

P

1

T

1

=

P

2

T

2

given constant

n

, and constant

V

, conditions that certainly obtain with a fixed volume light bulb.

And so

P

2

=

P

1

T

1

×

T

2

=

75

⋅

k

P

a

295

⋅

K

×

418

⋅

K

≅

100

⋅

k

P

a

.

Had the light bulb been sealed at normal pressure during its manufacture, what do you think might occur when it is operated?

5 0
3 years ago
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