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CaHeK987 [17]
2 years ago
14

Visible light is incident perpendicularly on a grating with 340 rulings/mm. What is the longest wavelength that can be seen in t

he m = 4 diffraction?
Physics
1 answer:
lakkis [162]2 years ago
4 0

Visible light is incident perpendicularly on a grating with 340 rulings/mm. 679 is the longest wavelength that can be seen in the m = 4 diffraction.

Waves spreading outward around obstructions is known as diffraction. Sound, electromagnetic radiation like light, X-rays, and gamma rays, as well as very small moving particles like atoms, neutrons, and electrons that exhibit wavelike qualities all exhibit diffraction.

Diffraction's effects can frequently be observed in daily life. The most spectacular diffraction examples include light, such as when a CD or DVD's tightly spaced tracks create the well-known rainbow pattern when viewed from different angles. Waves bend around gaps and barriers due to diffraction.

To learn more about diffraction please visit-
brainly.com/question/12290582
#SPJ4

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Sergio [31]

1. Due to the first law of Newton: there is a force that accelerate the body,

then the net force for 2 forces in opposite directions can calculated as

F_{net}=F_{1}-F_{2}=26-8=14N

2. For a force make an angle with the horizontal plane, we need to analysis the force into 2 perpendicular forces:

- In horizontal plane:

F_{x}=Fsin ( θ )= 67sin(73)=64N

then, as Q(1),

F_{net}=F_{1}-F_{2}=64-33=31 N

3. Because of the non change in the velocity, there is no acceleration

Then, there is no force is acted from the body

Hence all forces is according to the tension in the cable

F_{Tension}=420 N

4. A) As we solve the Q(2), we will analysis the un horizontal or vertical forces into 2 forces

F_{x}=Fsin ( θ )= 600sin(45)=424.264N

F_{y} = F sin ( θ )= 600cos45)=424.264N

Hence we have 2 opposite horizontal forces. also, 2 opposite vertical forces.

now, we calculate the net forces in each direction

F_{net in x}=F_{1}-F_{2}=424.264-250=174.264 N in east

F_{net in y}=F_{1}-F_{2}=-500-424.264=75.736 N in south

The total net force for perpendicular forces is calculated from the relation:  

F_{total}=\sqrt{F_{x} ^{2}+F_{y}^{2}}=\sqrt{174.264^{2}+75.736^{2}}=190N

B) To find the direction, we need to calculate the angle which the total force is made with the east direction of the x-axis (horizontal)

θ = tan^{-1}(\frac{F_{y}}{F_{x} })= tan^{-1}(\frac{-75.736}{174.264})=-23.48^{o}

That meas that the total force is made with the east direction of the x-axis angle equal to 23.48 for the south (the 4th quarter)

5. According to the third law of Newton, to make the balance the net force  equal to zero (for each action there is a reaction with the same amplitude and in opposite direction)

Then, F_{right}=F_{left}=55N

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olasank [31]

Answer:

OPTION A is the correct answer

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