Answer:
D. When the dense, positive alpha particle passes close to a positive nucleus of gold, the alpha particle repels and hits the screen at point X.
Explanation:
The height of the ball after the given time of motion is 3.275 m.
The given parameters;
- initial velocity of the ball, u = 4 m/s
- height of fall of the ball, h = 2.5 m
- time of motion, t = 0.5 s
The distance traveled by the ball is calculated as follows;
Thus, the height of the ball after the given time of motion is 3.275 m.
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Answer:
0.4
Explanation:
A concave lens is a diverging lens, so it will always have a negative focal length. Image distance is always negative for a concave lens because it forms virtual images.
From the lens formula;
1/f = 1/u+ 1/v
- 1/2 = 1/3 - 1/v
1/v = 1/3 + 1/2
v= 6/5
v= 1.2 cm
Magnification = image distance/object distance
Magnification = 1.2cm/3cm
Magnification = 0.4