Question

What is the molality of a solution consisting of 44.0 mL of benzene (C₆H₆; d = 0.877 g/mL) in 167 mL of hexane (C₆H₁₄;d = 0.660 g/mL)?

Answer 1

Molarityof the solution will be 907.35 m.

What is Molality?

Molaity is the no. Of moles of an compound is present in 1 kg solution .

Molality= no.0f moles / mass of the solution (in  kg)

The SI  unit of molality is m .

We have given here ,

Volume of benzene= 44.0ml

Density of benzene =0.877g/ mol

Volume of hexane =167 ml

Density of  hexane =0.660g/ mol

Mass of benzene  =  44×0.877

.                         →38.588 g

Mass of hexane→167×660

.                       → 110.220g

mass of the solution→148.808g

molar mass of the solution→78+ 86

.                             →164g/ mol

 Molality = 148.808/ 164×1000

→907.35m

So , molality will be 907.35 m

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