The ph before the addition of any Koh is<u> 10.105.</u>
Concentration is the abundance of a constituent divided by way of the overall volume of an aggregate. several sorts of mathematical descriptions may be outstanding: mass concentration, molar concentration, variety concentration, and extent awareness.
After the addition of 50 ml KOH,
moles of KOH = 50 * 0.13 =<u> 6.5 mmol </u>
<u>moles </u><u>of HClO = 50 * 0.13 = 6.5 mmol </u>
occurred hydrolysis solution,
pH = 0.5(14 + pKa + log [base conjugate])
pH = 0.5(14 + (- log (4 * 10^-8)) + log (6.5/(50 + 50)))
pH = <u>10.105</u>
The concentration of a substance is the quantity of solute found in a given amount of solution. Concentrations are normally expressed in terms of molarity, defined because of the variety of moles of solute in 1 L of answer.
The Concentration of an answer is a measure of the quantity of solute that has been dissolved in a given amount of solvent or answer. A concentrated answer is one that has a rather huge quantity of dissolved solute.
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A base and an Acid always react to form a salt and water
So, HCl + NaOH —> NaCl + HOH
The amount, in mg, of CO present in the room will be 191,520 mg.
<h3>Stoichiometric problem</h3>
The concentration of the gas in the room is 5.7 x 
mg/cm3.
The dimension of the room is 3.5 m x 3.0 m x 3.2 m. This is equivalent to 350 cm x 300 cm x 320 cm.
We can obtain the volume of the room as:
350 x 300 x 320 = 33,600,000 cm3
The concentration is in mg/cm3, meaning that it is mass/volume.
Thus:
mass = concentration x volume = 5.7 x mg/cm3 x 33,600,000 cm3
= 191,520 mg
The mass of CO in the room is 191,520 mg
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Answer: 733 kcal
Explanation:
According to a system used to calculate the available energy of foods, we have the following data:
- protein has 4 kcal/g
- carbohydrates has 4 kcal/g
- fat has 9 kcal/g
- alcohol has 7 kcal/g
So, we are told Jhon and his wife's dinner has:
- 55 g of carbohydrates
- 36 g of protein
- 27 g of fat
- 18 g of
Now we have to multiply these values by the kilocalories:
- (55 g of carbohydrates)(4 kcal/g)=220 kcal
- (36 g of protein)(4 kcal/g)=144 kcal
- (27 g of fat)(9 kcal/g)=243 kcal
- (18 g of alcohol)(7 kcal/g)=126 kcal
Then we have to sum all, giving the following result:
<h2>733 kcal</h2>
