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Vika [28.1K]
3 years ago
7

Matter can be pure or mixed

Chemistry
1 answer:
dimaraw [331]3 years ago
3 0

Matter can be pure, or it can be two or more substances mixed together.

is that what you need?

brainliest please?


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calculate the ph for each case in the titration of 50.0 ml of 0.130 m hclo(aq) with 0.130 m koh(aq). use the ionization constant
-BARSIC- [3]

The ph before the addition of any Koh is<u> 10.105.</u>

Concentration is the abundance of a constituent divided by way of the overall volume of an aggregate. several sorts of mathematical descriptions may be outstanding: mass concentration, molar concentration, variety concentration, and extent awareness.

After the addition of 50 ml KOH,

moles of KOH = 50 * 0.13 =<u> 6.5 mmol </u>

<u>moles </u><u>of HClO = 50 * 0.13 = 6.5 mmol </u>

occurred hydrolysis solution,

pH = 0.5(14 + pKa + log [base conjugate])

pH = 0.5(14 + (- log (4 * 10^-8)) + log (6.5/(50 + 50)))

pH = <u>10.105</u>

The concentration of a substance is the quantity of solute found in a given amount of solution. Concentrations are normally expressed in terms of molarity, defined because of the variety of moles of solute in 1 L of answer.

The Concentration of an answer is a measure of the quantity of solute that has been dissolved in a given amount of solvent or answer. A concentrated answer is one that has a rather huge quantity of dissolved solute.

Learn more about concentration here:-brainly.com/question/26255204

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4 0
1 year ago
Q2. Which of the following molecules may show.
jonny [76]

Answer:

I think is answer

CH3cl3

5 0
3 years ago
Write the chemical equations for the neutralization reactions that occurred when hcl and naoh were added to the buffer solution.
irga5000 [103]
A base and an Acid always react to form a salt and water

So, HCl + NaOH —> NaCl + HOH
5 0
3 years ago
The concentration of carbon monoxide (CO), a common air pollutant, is found in a room to be 5.7 x 10^-3 mg/cm^3. How many grams
damaskus [11]

The amount, in mg, of CO present in the room will be 191,520 mg.

<h3>Stoichiometric problem</h3>

The concentration of the gas in the room is 5.7 x 10^{-3} mg/cm3.

The dimension of the room is 3.5 m x 3.0 m x 3.2 m. This is equivalent to 350 cm x 300 cm x 320 cm.

We can obtain the volume of the room as:

                  350 x 300 x 320 = 33,600,000 cm3

The concentration is in mg/cm3, meaning that it is mass/volume.

Thus:

 mass = concentration x volume = 5.7 x 10^{-3} mg/cm3 x 33,600,000 cm3

                         = 191,520 mg

The mass of CO in the room is 191,520 mg

More on stoichiometric problems can be found here: brainly.com/question/14465605

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5 0
1 year ago
John and his wife are celebrating their first wedding anniversary. Their dinner consists of 55 grams of carbohydrates, 36 grams
nika2105 [10]

Answer: 733 kcal

Explanation:

According to a system used to calculate the available energy of foods, we have the following data:

  • protein has 4 kcal/g
  • carbohydrates has 4 kcal/g
  • fat has 9 kcal/g
  • alcohol has 7 kcal/g

So, we are told Jhon and his wife's dinner has:

  • 55 g of carbohydrates
  • 36 g of protein
  • 27 g of fat
  • 18 g of

Now we have to multiply these values by the kilocalories:

  • (55 g of carbohydrates)(4 kcal/g)=220 kcal  
  • (36 g of protein)(4 kcal/g)=144 kcal
  • (27 g of fat)(9 kcal/g)=243 kcal
  • (18 g of alcohol)(7 kcal/g)=126 kcal

Then we have to sum all, giving the following result:

<h2>733 kcal</h2>
4 0
3 years ago
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