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mariarad [96]
2 years ago
8

The lung volume that represents the maximum amount of exchangeable air is the _____

Physics
1 answer:
Savatey [412]2 years ago
5 0

The lung volume that represents the maximum amount of exchangeable air is the: <u>vital capacity</u>

<u></u>

The vital capacity is the volume of air that can be taken into the lungs by inhaling and expelling air by inspiration and expiration.

<h3>What are the lungs? </h3>

The lungs are one of the largest organs of the body and are in charge of the respiratory function. They have a spongy appearance and are located in the thorax, protected by the ribs, one on each side of the heart.

Learn more about the lungs at: brainly.com/question/27010145

#SPJ4

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A 1.5m wire carries a 7 A current when a potential difference of 87 V is applied. What is the resistance of the wire?
kramer

Answer:

Ohm's law states that I=V/R (Current=volts divided by resistance). Since we're looking for resistance, we'll rewrite it as R=V/I. Then just plug in the numbers; R=84/9, R= 9 1/3 or 28/3. The resistance of the wire is 9.33... or 9 1/3 ohm's, depending on how you wanna write it.

Hope it helped u if yes mark me BRAINLIEST!

Tysm!

I would appreciate it!

3 0
3 years ago
Read 2 more answers
In which condition is relative velocity known by adding the velocity od the first body and that of the second body ?​
Softa [21]

Answer:

when a two bodies A and B are moving at an angle 180° with each other then the relative velocity is the sum of bodies the velocity .i.e,

when the bodies move the opposite direction

then their relative velocity is the sum of individual velocities.

3 0
3 years ago
A constant net torque is exerted on an object. Which of the following quantities for the object cannot be constant? (Select all
prohojiy [21]

Answer:

A. kinetic energy

B. angular velocity

E. angular position

Explanation:

The quantities that cannot be constant if a constant net torque is exerted on an objecta are:

A. Kinetic energy. If a torque is applied, the linear or angular speed will be changing at a rate proportional to the torque, so the kinetic energy will change too.

B. Angular velocity. It will change at a rate equal to the torque.

C. Angular position. If the angular velocity changes, the angular position will change.

3 0
4 years ago
The tub of a washer goes into its spin-dry cycle, starting from rest and reaching an angular speed of 5.0 rev/s in 8.0 s. At thi
alisha [4.7K]

Answer:

The total number of revolution is 50 rev.

Explanation:

Given that,

Angular speed = 5.0 rev/s

Time = 8.0 s

We need to calculate the angular acceleration

Using equation of angular motion

\omega_{f}-\omega_{i}=\alpha t

Put the value into the formula

5.0-0=\alpha\times8.0

\alpha=\dfrac{5.0}{8.0}

\alpha=0.625\ rev/s^2

We need to calculate the angular displacement

Using equation of angular motion

\theta=\omega_{i}t+\dfrac{1}{2}\alpha t^2

Put the value into the formula

\theta=0+\dfrac{1}{2}\times0.625\times(8.0)^2

\theta=20\ rev

Now, The washer coming to rest from top spin

We need to calculate the angular acceleration

Using equation of angular motion

\omega_{f}-\omega_{i}=\alpha t

\alpha=\dfrac{\omega_{f}-\omega_{i}}{t}

\alpha=\dfrac{0-5}{12}

\alpha=−0.4167\ rev/s^2

We need to calculate the angular displacement

Using formula of displacement

\theta'=\omega_{i}t+\dfrac{1}{2}\alpha t^2

Put the value into the formula

\theta'=5\times12+\dfrac{1}{2}\times(-0.4167)\times12^2

\theta'=30\ rev

We need to calculate the total number of revolution

\theta''=\theta+\theta'

\theta''=20+30

\theta''=50\ rev

Hence, The total number of revolution is 50 rev.

5 0
4 years ago
calculate the weight of an object of mass 100 kg on the surface of a Planet whose mass and diameter are 4.8*10^24 kg and 12000km
PilotLPTM [1.2K]

The weight of an object mass of 100 kg on the surface of a Planet willl is 981 N.

<h3>What is weight?</h3>

The weight of matter is found as the product of the mass and the gravitational acceleration;

Given data;

Weight of an object,W =?

Mass,m = 100 kg

\rm W= mg \\\\ \rm W= 100  \ kg  \times 9.81 \ m/sec^2 \\\\ W=981 \ N

Hence the weight of an object willl be 981 N.

To learn more about the weight refer;

brainly.com/question/10069252

#SPJ1

6 0
2 years ago
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