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3 years ago

In which condition is relative velocity known by adding the velocity od the first body and that of the second body ?

Physics

1 answer:

Softa [21]3 years ago

3 0

Answer:

when a two bodies A and B are moving at an angle 180° with each other then the relative velocity is the sum of bodies the velocity .i.e,

when the bodies move the opposite direction

then their relative velocity is the sum of individual velocities.

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Molybdenum (Mo) has a BCC crystal structure, an atomic radius of 0.1363 nm, and an atomic weight of 95.94 g/mol. Compute and com

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Answer:

Solid State or Condense matter book

Explanation:

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4 years ago

Read 2 more answers

When the drivers pass each other, the driver of the red car is to toss a package of contraband to the other driver. To catch the

Brrunno [24]

Answer:

D=387.28m

Explanation:

At the moment where the toss is made $X_R = X_G$ , so we need both equations:

For the red car:

$X_R=\frac{a_R*t^2}{2}$ With initial speed of 0 and acceleration of 6.12m/s^2.

For the green car:

$X_G=Xo + V_G*t$ With $V_G = 60km/h*\frac{1000m}{1km} * \frac{1h}{3600s} = 16.66m/s$ and Xo = 200m

Since both positions will be the same:

$\frac{a_R*t^2}{2}=Xo+V_G*t$ Solving for t:

t1 = -5.8s and t1 =11.25s

Replacing t = 11.25 on either equation to find the displacement:

$D = X_R = \frac{a_R*t^2}{2} = 387.28m$

3 0

4 years ago

Draw the position vs. time graph for a person walking at a constant speed of 1m/s for 10 seconds. On the same axes, draw graph f

Leto [7]

In both scenarios, the position - time graph will be a linear graph, since the speed is constant, so your position is moving at a consistent pace.

7 0

3 years ago

What is the speed of light (in m/s) in air? (Enter your answer to at least four significant figures. Assume the speed of light i

jenyasd209 [6]

Answer:

The speed of light in air is 2.996x10⁸ m/s, and polystyrene is 1.873x10⁸ m/s.

Explanation:

To find the speed of light in air and in polystyrene we need to use the following equation:

$c_{m} = \frac{c}{n}$

Where:

$c_{m}$ : is the speed of light in the medium

n: is the refractive index of the medium

In air:

$c_{a} = \frac{c}{n_{a}} = \frac{2.997 \cdot 10^{8} m/s}{1.0003} = 2.996 \cdot 10^{8} m/s$

In polystyrene:

$c_{p} = \frac{c}{n_{p}} = \frac{2.997 \cdot 10^{8} m/s}{1.6} = 1.873 \cdot 10^{8} m/s$

Therefore, the speed of light in air is 2.996x10⁸ m/s, and polystyrene is 1.873x10⁸ m/s.

I hope it helps you!

8 0

3 years ago

A weight of 50.0 N is suspended from a spring that has a force constant of 210 N/m. The system is undamped and is subjected to a

Fittoniya [83]

Answer:

The maximum value of the driving force is 1044.01 N.

Explanation:

Given that,

Weight of the object, W = 50 N

Force constant of the spring, k = 210 N/m

The system is undamped and is subjected to a harmonic driving force of frequency 11.5 Hz.

Amplitude, A = 4 cm

We need to find the maximum value of the driving force. The force is given by the product of mass and maximum acceleration as :

$F=mA\omega^2$ .....(1)

A is amplitude

m is mass,

$m=\dfrac{W}{g}\\\\m=\dfrac{50}{10}\\\\m=5\ kg$

$\omega$ is angular frequency

Angular frequency is given by :

$\omega=2\pi f\\\\\omega=2\pi \times 11.5\\\\\omega=72.25\ rad/s$

Equation (1) becomes :

$F=5\times 0.04\times 72.25^2\\\\F=1044.01\ N$

So, the maximum value of the driving force is 1044.01 N.

6 0

3 years ago

In which condition is relative velocity known by adding the velocity od the first body and that of the second body ?​

In which condition is relative velocity known by adding the velocity od the first body and that of the second body ?