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1 year ago

Why is the center of the buffer region of a weak acid–strong base titration significant?

1 answer:

7 0

When a weak acid is titrated against a strong base, the pH of the solution rises, levels off through the buffer zone, and then rises quickly to reach the equivalence point.

<h3>What is titration?</h3>

Titration is a typical research center technique for quantitative investigation synthetic to decide the convergence of a recognized analyte. Titration is a crucial cycle in the creation of cheddar. For this situation, titration is significant while estimating the pH and acridity of the underlying milk being utilized to make the cheddar. Corrosive base titration is a quantitative investigation of convergence of an obscure corrosive or base arrangement. Titration, otherwise called titrimetry, is a typical lab strategy for quantitative substance investigation that is utilized to decide the convergence of a distinguished analyte. A reagent, called the titrant or titrator is ready as a standard arrangement. A known fixation and volume of titrant responds with an answer of analyte or titrand to decide focus. The volume of titrant responded is called titration volume.

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You might be interested in

N2(g) + 3H2(g) -> 2NH 3(g)

Nutka1998 [239]

Answer:

None of the options are correct. The correct answer is:

56.67g

Explanation:

N2 + 3H2 —> 2NH3

Molar Mass of NH3 = 14 + (3x1) = 14 + 3 = 17g/mol

Mass of NH3 from the balanced equation = 2 x 17 = 34g

Molar Mass of H2 = 2x1 = 2g/mol

Mass of H2 from the balanced equation = 3 x 2 = 6g

From the equation,

6g of H2 produced 34g of NH3.

Therefore, 10g of H2 will produce = (10 x 34)/6 = 56.67g of NH3

Therefore, 56.67g of NH3 are produced

5 0

3 years ago

Carbon dioxide (CO2) is a gaseous compound. Calculate the percent composition of this compound. Answer using three significant f

Tamiku [17]

Carbon dioxide is a gaseous molecule made up of the elements, C and O. Each mole of carbon dioxide has one mole C and two mole oxygen atoms.

Molar mass of carbon dioxide ( $CO_{2}$ )= $(1 * 12.01\frac{g}{mol}) +(2* 16\frac{g}{mol})=44.01\frac{g}{mol}$

Percentage by mass of carbon = $\frac{(1*12.01\frac{g}{mol}) }{44.01\frac{g}{mol} } *100=27.3%$

Percentage by mass of oxygen = $\frac{(2*16\frac{g}{mol})}{44.01\frac{g}{mol} } *100=72.7%$

Therefore C is 27.3 % and O is 72.7 % by mass in 1 mol CO $_{2}$

7 0

4 years ago

Read 2 more answers

A barium hydroxide solution is prepared by dissolving 2.06 g of Ba(OH)2 in water to make 32.9 mL of solution. What is the concen

navik [9.2K]

Answer: 1.36 M

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

$Molarity=\frac{n\times 1000}{V_s}$

where,

n = moles of solute

To calculate the moles, we use the equation:

moles of solute= $\frac{\text {given mass}}{\text {molar mass}}=\frac{2.06g}{171g/mol}=0.0120moles$

$Molarity=\frac{0.0120\times 1000}{32.9}=0.364M$

The balanced reaction between barium hydroxide and perchloric acid:

$2HCIO_4+Ba(OH_)2\rightarrow BaCIO_4+2H_2O$

To calculate the concentration of acid, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is $HClO_4$

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is $Ba(OH)_2$

We are given:

$n_1=1\\M_1=?\\V_1=8.50mL\\n_2=2\\M_2=0.364M\\V_2=15.9mL$

Putting values in above equation, we get:

$1\times M_1\times 8.50=2\times 0.364\times 15.9\\\\M_1=1.36M$

Thus the concentration of the acid is 1.36 M

4 0

3 years ago

Calculate the equilibrium number of vacancies per cubic meter for copper at 1000K. The energy for vacancy formation is 0.9eV/ato

nexus9112 [7]

Answer:

Therefore the equilibrium number of vacancies per unit cubic meter =2.34×10²⁴ vacancies/ mole

Explanation:

The equilibrium number of of vacancies is denoted by $N_v$ .

It is depends on

total no. of atomic number(N)
energy required for vacancy
Boltzmann's constant (k)= 8.62×10⁻⁵ev K⁻¹
temperature (T).

$N_v=Ne^{-\frac{Q_v}{kT} }$

To find equilibrium number of of vacancies we have find N.

$N=\frac{N_A\ \rho}{A_{cu}}$

Here ρ= 8.45 g/cm³ =8.45 ×10⁶m³

$N_A$ = Avogadro Number = 6.023×10²³

$A_{Cu}$ = 63.5 g/mole

$N=\frac{6.023\times 10^{23}\times 8.45\times 10^{6}}{63.5}$

$=8.01\times 10^{28$ g/mole

Here $Q_v$ =0.9 ev/atom , T= 1000k

Therefore the equilibrium number of vacancies per unit cubic meter,

$N_v=( 8.01\times 10^{28}) e^{-(\frac{0.9}{8.62\times10^{-5}\times 1000})$

=2.34×10²⁴ vacancies/ mole

3 0

3 years ago

A solution is prepared by dissolving 38.6 g sucrose (C12H22O11) in 495 g of water. Determine the mole fraction of sucrose if the

stiks02 [169]

Answer:

4.09×10⁻³ is the mole fraction of sucrose

Explanation:

Mole fraction = Moles of solute or solvent/ Total moles

Let's convert the mass to moles (mass / molar mass)

38.6 g / 342 g/m = 0.113 moles of sucrose

495 g / 18 g/m = 27.5 moles of water

Total moles = 0.113 m + 27.5 m = 27.0613 moles

Mole fraction of sucrose = Moles of sucrose / Total moles

0.113 m / 27.0613 moles = 4.09×10⁻³

8 0

3 years ago