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DENIUS [597]
3 years ago
13

Three hundred grams of aluminum are heated from −50 ◦c to 300 ◦c. if the specific heat of aluminum is 0.88 j/(g ◦c), what is the

change in entropy of the aluminum?
Chemistry
1 answer:
enyata [817]3 years ago
4 0
Q = mCΔT
Q is heat in Joules, m is mass, C is specific heat, and ΔT is change in temp

Q = (300g)(.88)(350 degrees) = 92400 J or 92.4 kJ
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