The three situations can be described as
a) If we have two white powders and wish to distinguish between the two : the combinations can be sugar / salt or sugar / baking soda or salt / baking soda
all are kitchen items so we can either taste them
or in case of baking soda we can add it in water and it will produce brisk effervescence.
b) IF we have to distinguish in a given set of two transparent liquids which appear to be water (example water and vinegar)
we can identify them with the taste
we can identify them based on pH (vinegar will be acidic)
c) We have to find adulteration in a given sample of food
like adulteration in milk
for example presence of soap in milk
We can add indicator like phenolphthalein which will bring a pink colour in milk if soap is present
Answer:
The sigma bonds are capable of rotating, the pi bonds not.
Explanation:
Sigma bonds are the strongest type of bonds, there are related to the overlapping in the atomic orbitals, and they can rotate. In the pi bound (that is a double bond), there are electrons moving on the molecule and it is not permitted the rotation on this type of bonds. Of the sigma bonds are capable of rotating while the pi bonds not.
Disgusting, depressing, and misery. Tap water is beyond formidable.
Answer:
D. Solution A has more concentrated acid than solution B and acid in solution A is also a weaker acid than that in solution B.
Explanation:
As it has been said in the question that the volume to reach the equivalence point of the solution A is twice the volume of solution B, this is because the acid in the solution A is more concentrated than B that's why more NaOH was required to reach to the equivalence point.
Since the pH at the equivalence point was greater for solution A that means the acid in solution A was a weak acid that's why the pH raised more as the NaOH was added to the solution.
