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Setler79 [48]
2 years ago
15

Give an example of a physical entity that is quantized. State specifically what the entity is and what the limits are on its val

ues.
Physics
2 answers:
konstantin123 [22]2 years ago
7 0

One example of a physical entity that is quantized is:

The amount of money in your pocket.

The amount can't have any fraction of 1 cent.  

Its value must be an integer-multiple of cents, or 0.01 dollar.    

When it increases or decreases, it jumps from one integer number of cents to the next integer number.  It doesn't "slide" from one to the next.  It can never have a value between two integer numbers of cents.

Bogdan [553]2 years ago
3 0

Answer:

A charge is a physical entity that has been quantized. The limits on its values are the value of a charged particle quantized in the state where 'n'...

Explanation:

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Assuming the ball's initial velocity was 51 ∘ above the horizontal and ignoring air resistance, what did the initial speed of th
Umnica [9.8K]

horizontal distance of home run is 400 ft = 122 m

height of the home run is 3 ft = 0.9 m

now the angle of the hit is 51 degree

now we have equation of trajectory of the motion

x = vcos\theta * t

y = v sin\theta * t - \frac{1}{2} gt^2

solving above two equations we have

y = xtan\theta - \frac{gx^2}{2v^2cos^2\theta}

now here we will plug in all data

0.9 = 122 tan51 - \frac{9.8 * 122^2}{2*v^2 * cos^251}

0.9 = 150.65 - \frac{184150.2}{v^2}

\frac{184150.2}{v^2} = 149.75

v = 35.1 m/s

<em>so the ball was hit with speed 35.1 m/s from the ground</em>

8 0
3 years ago
When 224-nm light falls on a metal, the current through a photoelectric circuit is brought to zero at a stopping voltage of 1.84
OLga [1]

Answer:

3.71 eV

Explanation:

λ = Wavelength of light = 224 nm = 224 x 10⁻⁹ m

c = speed of electromagnetic wave = 3 x 10⁸ m/s

V₀ = stopping potential = 1.84 volts

W₀ = Work function of the metal = ?

Using the equation

\frac{hc}{\lambda } = eV_{o} + W_{o}

\frac{(6.63\times 10^{-34})(3\times 10^{8})}{224\times 10^{-9} } = (1.6\times 10^{-19})(1.84) + W_{o}

W_{o} = 5.94 x 10⁻¹⁹

W_{o} = 3.71 eV

7 0
3 years ago
The voltage across the secondary winding is 10,000 V, and the voltage across the primary winding is 25,000 V. If the primary win
Allisa [31]

<u>Answer</u>

80 coils


<u>Explanation</u>

The turn rule of a transformer says that, the amount of voltage induced in the secondary coil is proportional to the number of coil. It is simplified by the ratio:

N<em>p/</em><em>N</em><em>s  =  </em><em>V</em><em>p/</em><em>V</em><em>s</em>

200/Ns  = 25,000/10,000

200 × 10,000  = 25,000Ns

2,000,000 = 25000Ns

Dividing both sides by 25,000,

Ns = 2,000,000/25,000

       = 80 coils




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