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aleksandr82 [10.1K]
3 years ago
5

Electric charges that are different attract each other.

Physics
2 answers:
n200080 [17]3 years ago
7 0

There are two forces between any two charges
or charged objects.

Each one exerts a force on the other one, and
the forces are equal.

If the charges are the same sign, the the forces push.

If the charges are different signs, then the forces pull.

Delvig [45]3 years ago
3 0
True? i'm not sure what you are asking for here but that is correct. opposite electric charges attract each other
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Summarize what you learned this week about the electromagnetic spectrum
svetoff [14.1K]

Answer:

I only really know the "How do we use these EM waves in our lives?" part srry

Explanation:

EM waves are used to make sure you cellphone, radio, TV, and etc. have service/ connection.

8 0
3 years ago
Read 2 more answers
A spotlight on the ground shines on a wall 12 m away. If a man 2 m tall walks from the spotlight toward the building at a speed
gregori [183]

Answer:

the rate of the change of the length of the shadow is - 0.8625 m/s.

The negative(-) sign means the length of the shadow decreases at a rate of 0.8625 m/s.

Explanation:

Given the data in the question;

Let x represent the man's distance from building,

initially x = 1m2

dx/d t= -2.3 m/s

Also Let y represent shadow height

so we determine dy/dt when x is 4m from the building

form the image description of the problem, we see two-like triangles with the same base and height ratios

so

 2 / (12-x) = y / 12

24 = y(12 - x )

y = 24 / (12-x)

dy/dt = 24/(12-x)² × dx/dt

Now at x = 4,

we substitute

dy/dt will be;

⇒ 24/(12 - 4)² × -2.3

= 24/64 - 2.3

= 0.375 × -2.3

dy/dt = - 0.8625 m/s

Therefore, the rate of the change of the length of the shadow is - 0.8625 m/s.

The negative(-) sign means the length of the shadow decreases at a rate of 0.8625 m/s.

5 0
3 years ago
1. The two images below show the area swept out by the same planet during two separate time spans. If the first picture represen
raketka [301]

Answer:

its A

Explanation:

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8 0
3 years ago
With the same block-spring system from above, imagine doubling the displacement of the block to start the motion. By what factor
Fofino [41]

Answer:

A)     K / K₀ = 4   b)     v / v₀ = 4

Explanation:

A) For this exercise we can use the conservation of mechanical energy

in the problem it indicates that the displacement was doubled (x = 2xo)

starting point. At the position of maximum displacement

      Em₀ = Ke = ½ k (2x₀)²

final point. In the equilibrium position

      Em_{f} = K = ½ m v²

        Em₀ = Em_{f}

        ½ k 4 x₀² = K

        (½ K x₀²) = K₀

         K = 4 K₀

          K / K₀ = 4

B) the speed value

          ½ k 4 x₀² = ½ m v²

          v = 4 (k / m) x₀

if we call

           v₀ = k / m x₀

          v = 4 v₀

         v / v₀ = 4

3 0
3 years ago
The mass of the particles that a river can transport is proportional to the sixth power of the speed of the river. A certain riv
kow [346]

Answer:

1.122 m/s

Explanation:

So usually a river with a speed of 1 meters per second can transport particle that weighs:

1^6 = 1 kg

If the particle is twice as massive as usual, then its weights would be 1 * 2 = 2kg

This means the river must be flowing at a speed of

2^{\frac{1}{6}} = 1.122 m/s

5 0
3 years ago
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