2/5 = .4
.4*100= 40%
Alex spends more time
Answer:
The maximum torque in the coil is 
.
Explanation:
Given that,
Number of turns in the circular coil, N = 50
Radius of coil, r = 5 cm
Magnetic field, B = 0.5 T
Current in coil, I = 25 mA
We need to find the magnitude of the maximum possible torque exerted on the coil. The magnetic torque is given by :
For maximum torque, 
So, the maximum torque in the coil is .
Human dignity and worth and social justice are TWO OF THE BASIC VALUES OF THE CODE OF ETHICS FOR SOCIAL WORK.
Social workers are those professionals, who promote social change by helping to relieve hardship and suffering. Social work is committed to five basic values, which are:
1. Human dignity and worth
2. Social justice
3. Service to humanity
4. Integrity
5. Competence.
The human dignity and self worth value holds that all human beings have intrinsic value, right to well being, right to self fulfillment and control over their own lives.
The social justice value states that there should be fair and equitable distribution of resources to meet basic human needs and all citizens should have access to public resources in order to achieve full potential.
Answer:
a) that laser 1 has the first interference closer to the central maximum
c) Δy = 0.64 m
Explanation:
The interference phenomenon is described by the expression
d sin θ = m λ
Where d is the separation of the slits, λ the wavelength and m an integer that indicates the order of interference
For the separation of the lines we use trigonometry
tan θ = sin θ / cos θ = y / x
In interference experiments the angle is very small
tan θ = sin θ = y / x
d y / x = m λ
a) and b) We apply the equation to the first laser
λ = d / 20
d y / x = m d / 20
y = m x / 20
y = 1 4.80 / 20
y = 0.24 m
The second laser
λ = d / 15
d y / x = m d / 15
y = m x / 15
y = 0.32 m
We can see that laser 1 has the first interference closer to the central maximum
c) laser 1
They ask us for the second maximum m = 2
y₂ = 2 4.8 / 20
y₂ = 0.48 m
For laser 2 they ask us for the third minimum m = 3
In this case to have a minimum we must add half wavelength
y₃ = (m + ½) x / 15
m = 3
y₃ = (3 + ½) 4.8 / 15
y₃ = 1.12 m
Δy = 1.12 - 0.48
Δy = 0.64 m
