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Evgen [1.6K]
1 year ago
15

water interacts with polar substances like –oh groups but not with non-polar substances like methyl (−ch3) or ethyl groups (−ch2

). using this information, select the molecules that will easily dissolve in water based on polarity not on size. check all that apply.
Chemistry
1 answer:
Brilliant_brown [7]1 year ago
7 0

CH3OH and CH3CH2CH2OH will easily dissolve in water based on polarity not on size.

<h3>What is Polarity ?</h3>

In chemistry, polarity describes the type of bonds that exist between atoms. Atoms share electrons when they join forces to form chemical bonds. When one of the atoms applies a stronger attractive force to the bond's electrons, a polar molecule is created.

  • For instance, the chlorine atom is slightly negatively charged while the hydrogen atom in hydrogen chloride is slightly positively charged.

  • Water is polar due to its form even though its molecules have no net charge. The molecule's hydrogen ends are positive, and its oxygen ends are negative. Water molecules are drawn to other polar molecules and to one another as a result.

Learn more about Polarity here:

brainly.com/question/26849258

#SPJ4

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The answer is 3.10 because it's still the same amount moles of iron.
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3 years ago
In the graphic, 195 represents the _______.
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Answer:

ITS ANSWER IS

OPTION B. ATOMIC NUMBER

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HBr + H₂SO₄ SO₂ + Br₂ + H₂O<br><br> whats the oxidizing agent and whats the reducing agent?
seropon [69]

Answer:

HBr + H₂SO₄ → SO₂ + Br₂ + H₂O An oxidizing agent is a substance that itself becomes reduced and oxidizes the other chemical species in the reaction mixture. A reducing agent is similar, except that it becomes oxidized and reduces the other substance. In the reaction, the valency of bromine changes from -1 to 0, so it is oxidized

Explanation:

3 0
3 years ago
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The heat required to raise the temperature of 12g of water from 16 C to 21 C is:
NemiM [27]

Answer:

The heat required to raise the temperature of 12g of water from 16 C to 21 C is 60 cal.

Explanation:

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

There is a direct proportional relationship between heat and temperature. The constant of proportionality depends on the substance that constitutes the body as on its mass, and is the product of the specific heat by the mass of the body. So, the equation that allows calculating heat exchanges is:

Q = c * m * ΔT

where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation.

In this case, you know:

  • Q=?
  • c= 4.186 \frac{J}{g*C}
  • m= 12 g
  • ΔT=Tfinal - Tinitial= 21 °C - 16°C= 5 °C

Replacing:

Q= 4.186 \frac{J}{g*C} *12 g *5 °C

Solving:

Q=251.16 J

Since 1 J is equal to 0.2388 cal, then the following rule of three can be applied: if 1 J is equal to 0.2388 cal, then 251.16 J to how many cal are?

cal=\frac{251.16 J * 0.2388 cal}{1 J}

cal= 59.98 ≅ 60

<u><em>The heat required to raise the temperature of 12g of water from 16 C to 21 C is 60 cal.</em></u>

3 0
3 years ago
941 milliliters is the same as: cm3 and L
Nutka1998 [239]

For this case, we must take into account the following conversion factors:

1 mL = 1 cm ^ 3

1000 mL = 1 L

Therefore, by applying the conversion factors we have:

For cubic centimeters:

(941mL) (1\frac{cm^3}{mL}) = 941cm ^ 3

For liters:

(941mL) (\frac{1}{1000}\frac{L}{mL}) = 0.941L

Answer:

941 milliliters is the same as:

941cm ^ 3

0.941L

6 0
3 years ago
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