Answer:

Explanation:
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In this case, since the combustion reaction of methanol is:

In such a way, since there is 1:3/2 mole ratio between methanol and oxygen, we can compute the moles of oxygen that are needed to burn 2.56 moles of methanol as shown below:

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I am guessing you want us to balance this equation so.
To balance, we add another molecule of HCl to the left side of the equation and another molecule of water (H20) to the right side of the equation to give:
<span>Mg(OH)2 + 2HCl = MgCl2 + 2H20 </span>
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