Answer:
Electrons accelerated to high velocities travel in straight lines through an empty cathode ray tube and strike the glass wall of the tube, causing excited atoms to fluoresce or glow.
Answer:
31.92 h
Explanation:
We'll begin by calculating the number of half-lives that has elapsed. This can be obtained as follow:
Original amount (N₀) = 1
Amount remaining (N) = ⅛
Number of half-lives (n) =?
N = 1/2ⁿ × N₀
⅛ = 1/2ⁿ × 1
Cross multiply
2ⁿ = 8
Express 8 in index form with 2 as the base.
2ⁿ = 2³
n = 3
Thus, 3 half-lives has elapsed.
Finally, we shall determine the time. This can be obtained as follow:
Half-life (t½) = 10.64 h
Number of half-lives (n) = 3
Time (t) =?
n = t / t½
3 = t / 10.64
Cross multiply
t = 3 × 10.64
t = 31.92 h
Therefore, it will take 31.92 h for lead-212 to decay to one-eighth its original strength.
ANY Zinc atom has 30 protons in its nucleus, no matter
what the atom's net charge is.
If there are more or less than 30 protons in the nucleus,
then it's an atom of some other element, not Zinc.
Answer:
The coefficient of kinetic friction is .0204081633 and the firction acting upon the object is 1 N
Explanation:
To figure this out I started off with Newton's Second Law F= ma.
(11-x)=5*2. *x is the amount of force that kinetic friction applies on the object
x=1 N
Since F=1 and Friction=Normal-Force*Coifficient-Of-Friction
1=5g(mu)
mu=.0204081633
Hope this helps