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anzhelika [568]
3 years ago
15

The lifetimes of light bulbs are normally distributed with a mean of 1490 hours and a standard deviation of

Physics
1 answer:
Llana [10]3 years ago
5 0

Answer:

1) Proportion of light bulbs lasting less than 1380 hours.

P(X<1380) = 0.2317(4dp)

2)The longest lasting 5% of light bulbs last 1736.7 hours or more

3) The middle 85% of light bulbs last between 1274.1 and 1705.9 hours

4) Proportion of light bulbs lasting between 1310 hours and 1680 hours is 0.7823 (4 dp)

5) Proportion of light bulbs lasting more than 1680 hours is 0.1026(4dp)

6) The shortest lasting 10% of light bulbs last 1297.8 hours.

Explanation:

The calculations are handwritten and attached as files to this solution. Check the files below for all the workings

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The correct answer is C. Plug in x and y value for answers to see if they work. For example, 9/3 = 3. So C is the answer.
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2×3.14√(1.0m/(9.8〖ms〗^(-1) )=)
il63 [147K]

This is the period in a simple harmonic motion which is 2 seconds in this question.

<h3>What is Period ?</h3>

The period of an oscillatory object can be defined as the total time taken  by a vibrating body to make one complete revolution about a reference point.

We are given the below question

2×3.14√(1.0m/(9.8〖ms〗^(2) )= T

This question can as well be expressed as

2π√(L/g) which is equal to period T.

In a nut shell, Period T = 2×3.14√(1.0m/9.8)

T = 6.28√0.102

T = 6.28 × 0.32

T = 2.006 s

Therefore, the period T of the oscillation is 2 seconds approximately.

Learn more about Period here: brainly.com/question/12588483

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