Answer
given,
height of counter = 1.20 m
horizontal distance from base = 1.6 m
a) velocity of mug = ?
using equation of motion
t = 0.495 s
speed of the mug
s_x = v x t
1.6 = v x 0.495
v = 3.23 m/s
b) final velocity of mug in y direction
again using equation of motion
v² = u² + 2 a s
v²= 0 + 2 x 9.8 x 1.2
v = √23.52
v_y = 4.85 m/s
now, direction
The initial velocity of a car that accelerates at a constant rate of 3m/s² for 5 seconds is 12m/s.
CALCULATE INITIAL VELOCITY:
The initial velocity of the car can be calculated by using one of the equation of motion as follows:
V = u + at
Where;
- V = final velocity (m/s)
- u = initial velocity (m/s)
- a = acceleration due to gravity (m/s²)
- t = time (s)
According to this question, a car accelerates at a constant rate of 3 m/s² for 5 seconds. If it reaches a velocity of 27 m/s, its initial velocity is calculated as follows:
u = v - at
u = 27 - 3(5)
u = 27 - 15
u = 12m/s.
Therefore, the initial velocity of a car that accelerates at a constant rate of 3m/s² for 5 seconds is 12m/s.
Learn more about motion at: brainly.com/question/974124
Answer:
1.805 mm
Explanation:
Extension in the steel wire = WL_{steel}/AE_{steel}
Extension in the aluminium wire = WL_{Al}/AE_{Al}
Total extension = W/A * (L_{steel}/E_{steel} + L_{Al}/E_{Al})
we have:
W = mg
W = 5 × 9.8
W = 49 N
Area A = π/4 × (0.001)²
= 7.85398 × 10 ⁻⁷ m²
Total extension = W/A * (L_{steel}/E_{steel} + L_{Al}/E_{Al})
Total extension = 49/ 7.85398 × 10 ⁻⁷ ( (1.5/ 200×10⁹) + 1.5/ 70×10⁹))
Total extension = 0.0018048
Total extension = 1.805 mm
Thus, the total extension = the resulting change in the length of this composite wire = 1.805 mm
Answer:
2. 10.1376
Explanation:
10 to the -3 power is 0.01
1.32 times 0.01 is 0.0132
teaspoons in a gallon - 768
0.0132 times 768 is 10.1376
Got the first one; can you try the rest?
Most pictures used as the milky way are actually just pictures of other galaxies (such as Andromeda) that we just figure are similar enough to ours.
<span>We can take a side ways photo of our own galaxy, but not a front view. </span>