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3 years ago

Pendulum clocks generally run fast in winter and slow in summer

2 answers:

6 0

False. In the winter, the length of the pendulum decreases and its time period decreases. In the summer, the length of the pendulum increases and its time period increases.

Harman [31]3 years ago

5 0

If the question is true or false then the answer is true

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An object is at rest when it undergoes a constant acceleration of 13 m/s ^ 2 for 5.0 seconds. How far will it have traveled duri

Orlov [11]

Answer:

162.5 m is the distance traveled by an object.

Explanation:

Given that,

An object's constant acceleration (a) is $13m/s^2$ .

The time (t) it traveled is 5 seconds.

The object is at rest that is "initial velocity" (u) is 0 m/s.

To find the distance traveled use the below formula,

$s=ut+\frac{1}{2}at^2$

Where, "s" is distance traveled, "u" is initial velocity, "a" is acceleration and "t" is time taken.

Substitute the given values in the above formula,

$s=0\times5+\frac{1}{2}\times13\times 5^2$

$s=0+\frac{1}{2}\times13\times 25$

$s=0+\frac{1}{2}\times325$

s = 162.5 m

Therefore, distance traveled is 162.5 m.

3 0

3 years ago

You are towing a skier with a pwc and have an observer on board as required. how many people must the pwc be rated to carry

Lostsunrise [7]

When towing a skier with a personal water craft with an observer on board, the people in the personal water craft must only carry three to five people for there is only a limited space of people to be carried on board for it could cause conflict on board when there a lot of people of board.

3 0

3 years ago

A mass m is attached to an ideal massless spring. When this system is set in motion, it has a period t. What is the period if th

Blizzard [7]

If a mass m is attached to an ideal massless spring and has a period of t, then the period of the system when the mass is 2m is $\sqrt{2}t$ .

Calculation:

Step-1:

It is given that a mass m is attached to an ideal massless spring and the period of the system is t. It is required to find the period when the mass is doubled.

The time it takes an object to complete one oscillation and return to its initial position is measured in terms of a period, or T.

It is known that the period is calculated as,

$T=2 \pi \sqrt{\frac{m}{k}}$

Here m is the mass of the object, and k is the spring constant.

Step-2:

Thus the period of the system with the first mass is,

$t=2 \pi \sqrt{\frac{m}{k}}$

The period of the system with the second mass is,

$\begin{aligned}\\t^'&=2 \pi \sqrt{\frac{m}{k}}\\&=\sqrt{2}\times2 \pi \sqrt{\frac{2m}{k}}\\&=\sqrt{2}\times t\end{aligned}$

Then the period of the system with the second mass is $\sqrt{2}$ times more than the period of the system with the first mass.

Learn more about period of a spring-mass system here,

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5 0

1 year ago

WILL MARK BRAINLIEST FOR 2 QUESTIONS!!

Irina18 [472]

1) Work is the scalar quantity

2) The ideal mechanical advantage of the ramp is 2

Explanation:

In physics, there are two types of quantities:

- Scalar quantity: a scalar quantity is a quantity having only a number and its units. Therefore, it has no direction. Examples of scalar quantities are: distance, speed, energy, mass, temperature...

- Vector quantity: a vector quantity is a quantity having both a magnitude (number+units) and a direction. Examples of vector quantities are: displacement, velocity, force, acceleration...

Let's analyze now the quantities given:

- work : it has only a magnitude, so it is a scalar

- displacement : it has a magnitude and a direction, so it is a vector

- parallel component of force : it has a magnitude and a direction, so it is a vector

- perpendicular component of force: it has a magnitude and a direction, so it is a vector

The ideal mechanical advantage (IMA) of a machine is the mechanical advantage in absence of frictional forces, so when there are no loss of energy.

For a ramp, the IMA is calculated as

$IMA=\frac{L}{h}$

where

L is the length of the ramp

h is its height

For the ramp in this problem, we have

L = 6.00 m

h = 3.00 m

Therefore, its ideal mechanical advatnage is

$IMA=\frac{6}{3}=2$

Learn more about levers and other machines:

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7 0

3 years ago

A 1400 kg car driving at 25 m/s slams on its brakes. The coefficient of kinetic friction between the tires and the road is 0.7.

tamaranim1 [39]

The acceleration of the car is 6.86 m/s² and the time taken for the car to stop is 3.64 s.

The given parameters;

mass of the car, m = 1400 kg
Initial velocity of the car, u = 25 m/s
coefficient of kinetic friction, μ = 0.7

The acceleration of the car is calculated as follows;

a = μg

a = 0.7 x 9.8

a = 6.86 m/s²

The time taken for the car to stop is calculated by using Newton's second law of motion;

F = ma

$F = \frac{mv}{t} \\\\ma = \frac{mv}{t}\\\\a = \frac{v}{t} \\\\t = \frac{v}{a} \\\\t = \frac{25}{6.86} \\\\t = 3.64 \ s$

Thus, the acceleration of the car is 6.86 m/s² and the time taken for the car to stop is 3.64 s.

Learn more here:brainly.com/question/19887955

5 0

3 years ago