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3 years ago

Pendulum clocks generally run fast in winter and slow in summer

2 answers:

6 0

False. In the winter, the length of the pendulum decreases and its time period decreases. In the summer, the length of the pendulum increases and its time period increases.

Harman [31]3 years ago

5 0

If the question is true or false then the answer is true

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To cross the river a swimmer chooses the direction minimizing the amount of time spent in the water. The swimmer swims at a cons

Lynna [10]

Answer:

304 meters downstream

Explanation:

The given parameters are;

The speed of the swimmer = 2.00 m/s

The width of the river = 73.0 m

The speed of the river = 8.00 m/s

Therefore;

The direction of the swimmer's resultant velocity = tan⁻¹(8/2) ≈ 75.96° downstream

The distance downstream the swimmer will reach the opposite shore = 4 × 73 = 304 m downstream

The distance downstream the swimmer will reach the opposite shore = 304 m downstream

6 0

3 years ago

1. The planet Jupiter completes a revolution of the sun in 11.5 years. Express it in seconds. Given that one year= 3.154 × 10^7

xenn [34]

Answer:

The planet Jupiter completes one revolution of the sun in 362710000 seconds. Long time, right?

Explanation:

3.154x10^7=3.154x10000000=31540000

11.5x31540000=362710000

7 0

2 years ago

Which statement is true about planets with longer orbits in the solar system?

Yakvenalex [24]

Answer:

D They have longer seasons

Explanation:

I think this because the days will be longer so that means that the seasons will change also.

5 0

3 years ago

Read 2 more answers

A person can jump a maximum horizontal distance (by using a 45◦ projectile angle) of 5 m on Earth. The acceleration of gravity i

snow_lady [41]

Answer:30 m

Explanation:

Given

Maximum Horizontal distance is 5 m on earth

launching angle $=45^{\circ}$

Acceleration due to gravity on earth is $9.8 m/s^2$

Acceleration due to gravity on moon is $\frac{9.8}{6}=1.63 m/s^2$

Range of projectile is given by

$R=\frac{u^2\sin 2\theta }{g}$

$R_{earth}=\frac{u^2\sin 2\theta }{g}=5$ ----1

$R_{moon}=\frac{u^2\sin 2\theta }{\frac{g}{6}}$ -----2

Divide 1 & 2

$\frac{5}{R_{moon}}=\frac{1}{6}$

$R_{moon}=30 m$

4 0

3 years ago

A compound is discovered and its molecular weight is determined to be 526g/mol. however, one of the elements has not yet been id

AfilCa [17]

Sulphur

The missing element is sulphur

Here the compound is composed of element X and chlorine.

it is given,

XCl (6) ----> 6Cl

mass = 13.1%

it is X and Cl = 100%-13.10%

= 86.90%

chlorine = 86.90

X = 13.10

We assume 100g of sample

so according to the above solved data, in 100g of sample we have 86.90 g of chlorine.

now we split that chlorine into two moles of chlorine.

Every mole of sale has 35.45 grams of sales. 2.451 moles of seal are mine after that.
We are aware that cl is six times more than X. To find the moles of X, I must divide this number by six.
we discover that we have 0.4086 moles of X when we divide this by six.
We obtain those moles of X from 13.10 g of X.
Given that Mueller masses grams per mole, I can compute the molar mass.
13.10 grams of X are contained in 0.4086 moles of X.
Or, to put it another way, each remote has a molar mass of 32–06 grams.
The element with this molar mass is sulfur, as I can see from the periodic table.
Okay, so the element we're looking for in this situation is sulfur.

To learn more about finding missing element visit;

brainly.com/question/14238796

#SPJ4

7 0

1 year ago