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bearhunter [10]
2 years ago
12

Plan a controlled experiment to investigate how an object’s position is related to the amount of its potential energy by measuri

ng how high the ball bounces in the simulation. Choose at least four heights from which you will drop the ball. Describe your experiment.
Physics
1 answer:
igor_vitrenko [27]2 years ago
3 0

Answer:

Feeling like an addict that ain't had it, up and at it in a minute

If it hadn't been invented, my limit wouldn't be infinite

I'm feeling like an infant in a womb

I'ma be here 'til the tomb

Lately I've been in my room

Lookin' and lookin' at records on the wall

Hold up

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If the speed of a ball increased from 1m/s to 4m/s, by how much would the kinetic energy increase
GREYUIT [131]
In 16 times
KE= o.5 m times V squared
6 0
2 years ago
Joe is trying to soup up his dragster. He knows that the time needed for the car to go from 0 to 100 miles per hour varies inver
Tatiana [17]

Translating the first sentence into equation we get, t = k(1/h) where t is time in seconds, k is the constant and h is the horsepower. Substituting the values in the equation we have, 12s = k(1/200) we have a k = 2400 seconds – hp. To get the time at 240 hp we use the equation above and the constant, we get, t = (2400 seconds-hp)(1/240hp) t = 10seconds.

6 0
3 years ago
Robin would like to shoot an orange in a tree with his bow and arrow. The orange is hanging yf=5.00 myf=5.00 m above the ground.
tensa zangetsu [6.8K]

Answer:

h' = 55.3 m

Explanation:

First, we analyze the horizontal motion of the projectile, to find the time taken by the arrow to reach the orange. Since, air friction is negligible, therefore, the motion shall be uniform:

s = vt

where,

s = horizontal distance between arrow and orange = 60 m

v = initial horizontal speed of the arrow = v₀ Cos θ

θ = launch angle = 30°

v₀ = launch speed = 35 m/s

Therefore,

60 m = (35 m/s)Cos 30° t

t = 60 m/30.31 m/s

t = 1.98 s

Now, we analyze the vertical motion to find the height if arrow at this time. Using second equation of motion:

h = Vi t + (1/2)gt²

where,

Vi = Vertical Component of initial Velocity = v₀ Sin θ = (35 m/s)Sin 30°

Vi = 17.5 m/s

Therefore,

h = (17.5 m/s)(1.98 s) + (1/2)(9.81 m/s²)(1.98 s)²

h = 34.6 m + 19.2 m

h = 53.8 m

since, the arrow initially had a height of y = 1.5 m. Therefore, its final height will be:

h' = h + y

h' = 53.8 m + 1.5 m

<u>h' = 55.3 m</u>

4 0
2 years ago
Technician A says crimping solderless connections is the best method of splicing wires. Technician B says crimping should not be
algol13

Answer:

Technician b is correct.

Explanation:

Crimping cable allows a firm connection in mechanical terms and allows a low resistance path for the signal or the current flow, solder although it is better in terms of electrical conduction, can be impractical if the cable is subjected to excessive movement.

A crimped cable with excessive movement can also be easily broken at the ends, where it joins the part of the cable that is crimped, for this reason, a cable that is in excessive motion is recomended to be spliced ​​by joining cable with cable .

In order to decide which metod is better for splicing cables its necessary to evaluate each situation separatly.

7 0
3 years ago
A 67-kg base runner begins his slide into second base when he is moving at a speed of 3.6 m/s. The coefficient of friction betwe
USPshnik [31]

Answer:

434.16 Joules

Explanation:

u = Initial velocity

v = Final velocity

m = Mass of person

From work-energy theorem

KE=\frac{1}{2}m(v^2-u^2)\\\Rightarrow KE=\frac{1}{2}\times 67\times (3.6^2-0)\\\Rightarrow KE=434.16\ Joules

The runner loses 434.16 Joules of mechanical energy.

W=F\times s\\\Rightarrow F=\frac{W}{s}\\\Rightarrow \mu mg=\frac{W}{s}\\\Rightarrow s=\frac{W}{\mu mg}\\\Rightarrow s=\frac{434.16}{0.7\times 67\times 9.81}\\\Rightarrow s=0.94364\ m

He slides 0.94364 m

4 0
3 years ago
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