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2 years ago

What is the term for the number of protons in the nucleus of each atom of an element?

Chemistry

1 answer:

xxTIMURxx [149]2 years ago

5 0

Answer:

atomic number

Explanation:

atomic number is the number of protons

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The table shows data for two groups of plants one grown with fertilizer and the other without fetalizer was the mean height of t

Dmitrij [34]

Answer:

D is the correct answer.

Explanation:

I took the test on A pex. Everyone make sure you look at your answers. They are NOT always in the same order.

8 0

2 years ago

PLEASE HELPP ASAP!!!!!What is the equation for density A. D=M/V B. D=V/M C. D= M/V2 D. D=1/2 MV2

mestny [16]

The correct answer is option A.

D = M/V

The density of a substance is the ratio of its mass to its volume.

Density = mass / volume

or D = M/V

The unit of density is gram per milliliter or g/ml, when mass is expressed in gram or g and the volume is expressed in milliliter ml.

If we know the mass and volume of a substance we can calculate its density using the formula for density.

8 0

3 years ago

Hydrogen has three isotopes 1H, 2H, and 3H. What is the difference between these three isotopes?

Leona [35]

The main difference between the 3 isotopes of hydrogen are the number of neutrons in the nucleus. Hydrogen has no neutrons, Deuterium has one neutron, and tritium has two neutrons. All three have one proton and one electron.

4 0

3 years ago

Diatomic iodine [I2] decomposes at high temperature to form I atoms according to the reaction I2(g)⇌2I(g), Kc = 0.011 at 1200∘C

umka2103 [35]

Answer:

The concentration of I at equilibrium = 3.3166×10⁻² M

Explanation:

For the equilibrium reaction,

I₂ (g) ⇄ 2I (g)

The expression for Kc for the reaction is:

$K_c=\frac {\left[I_{Equilibrium} \right]^2}{\left[I_2_{Equilibrium} \right]}$

Given:

$\left[I_2_{Equilibrium} \right]$ = 0.10 M

Kc = 0.011

Applying in the above formula to find the equilibrium concentration of I as:

$0.011=\frac {\left[I_{Equilibrium} \right]^2}{0.10}$

So,

$\left[I_{Equilibrium} \right]^2=0.011\times 0.10$

$\left[I_{Equilibrium} \right]^2=0.0011$

$\left[I_{Equilibrium} \right]=3.3166\times 10^{-2}\ M$

<u>Thus, The concentration of I at equilibrium = 3.3166×10⁻² M</u>

3 0

4 years ago

sample of atmospheric gas collected at an industrial site is stored in a 250 mL amber glass bottle that has a pressure of 1.02 a

Nady [450]

Answer:- New pressure is 0.942 atm.

Solution:- The volume of the glass bottle would remain constant here and the pressure will change with the temperature.

Pressure is directly proportional to the kelvin temperature. The equation used here is:

$P_1T_2=P_2T_1$

Where, $T_1$ and $T_2$ are initial and final temperatures, $P_1$ and $P_2$ are initial and final pressures.

$T_1$ = 20.3 + 273.15 = 293.45 K

$T_2$ = -2.0 + 273.15 = 271.15 K

$P_1$ = 1.02 atm

$T_2$ = ?

Let's plug in the values in the equation and solve it for final pressure.

$1.02atm(271.15K)=P_2(293.45K)$

$P_2=\frac{1.02atm*271.15K}{293.45K}$

$P_2$ = 0.942 atm

So, the new pressure of the jar is 0.942 atm.

5 0

4 years ago