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Fed [463]
2 years ago
10

Potassium nitrate decomposes on heating, producing potassium oxide and gaseous nitrogen and oxygen:

Chemistry
1 answer:
ahrayia [7]2 years ago
4 0

To produce 56.6 kg of oxygen,  moles of KNO₃ = 142.915 kg

This is a stoichiometric kind of question where everything should be converted into moles in order to proceed on with the calculations.

First you find the number of moles of oxygen using the following formula:

Mole (mol) = Mass (g) / Molar Mass (g/mol)

For oxygen, the molar mass is 32g/mol.

Therefore the number of moles in 56.6 kg of oxygen is :

(56.6 × 1000)/32

= 1768.75

From the reaction equation, the ratio of KNO_{3} to O2 is 4:5.

Thus the number of moles of KNO_{3} is

1768.75 × 4/5

= 1415 mol.

If you are looking for the mass of  KNO_{3} needed then Mass (g)

= Mole (mol) × Molar Mass (g/mol),

1415 ×101 = 142,915g

= 142.915kg

What happens to potassium nitrate when heated?

When potassium nitrate is heated, it decomposes into potassium nitrite and oxygen. Write a balanced equation for this reaction and add the state symbols of the reactants and products.

Learn more about molar mass :

brainly.com/question/24236159

#SPJ4

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What is the pH of a KOH solution that has [H ] = 1. 87 × 10–13 M? What is the pOH of a KOH solution that has [OH− ] = 5. 81 × 10
vlada-n [284]

pH is the hydrogen ion concentration and pOH is the hydroxide ion concentration in the solution. pH KOH is 12.73, pOH KOH is 2.24 and pH NaCl is 7.

<h3>What are pH and pOH?</h3>

pH is the negative log of the hydrogen ion concentration and pOH is the negative log of the hydroxide ion concentration.

The relation between the pH and pOH can be given as, \rm pOH = 14 - pH

The pH of KOH can be calculated by the formula,

\rm pH = \rm -log [H^{+}]

In the first case, the concentration of the KOH is 1. 87 \times  10^{-13}\;\rm  M

Substituting values in the equation:

\begin{aligned} \rm pH &= \rm -log [H^{+}]\\\\&= \rm -log [1. 87 \times  10^{-13}\;\rm  M ]\\\\&= 12.73\end{aligned}

Hence, the pH of KOH is 12.73.

<u />

pOH of KOH can be calculated by the formula,

\rm pOH = \rm -log [OH^{-}]

The hydroxide concentration of the KOH solution is 5. 81 \times 10^{-3}\;\rm  M

Substituting value in the equation:

\begin{aligned} \rm pOH &= \rm -log [OH^{-}]\\\\&= \rm -log [5. 81 \times 10^{-3}\;\rm  M ]\\\\&= 2.24 \end{aligned}

Hence, the pOH of KOH is 2.24

<u />

The pH of NaCl can be calculated by the formula,

\rm pH = \rm -log [H^{+}]

In the third case, the concentration of the NaCl is 1. 00\times 10^{-7}\;\rm  M

Substituting values in the equation:

\begin{aligned} \rm pH &= \rm -log [H^{+}]\\\\&= \rm -log [1. 00 \times  10^{-7}\;\rm  M ]\\\\&= 7 \end{aligned}

Hence, the pH of KOH is 7.0.

Therefore, KOH is basic and NaCl is approximately neutral.

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brainly.com/question/13885794

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