207.217 amu
Work:
203.973 amu *(0.014) = 2.855 amu
205.974 amu *(0.241) = 49.639 amu
206.976 amu *(0.221) = 45.741 amu
207.977 amu *(0.524) = 108.979 amu
2.855 + 49.639 + 45.741 + 108.979 = 207.217 amu
Answer:
The volume of the vessel is 250 L
Partial pressure of hydrogen = 189 torr
Explanation:
Using Boyle's law

Given ,
V₁ = 20.0 L
V₂ = ?
P₁ = 25 atm
P₂ = 2 atm
Using above equation as:




<u>The volume of the vessel is 250 L.</u>
According to Dalton's law of partial pressure:-

So, according to definition of mole fraction:

Also,
Mole fraction of H₂ = 1 - Mole fraction of He = 1 - 0.75 = 0.25
So,
Total pressure = 756 torr
Thus,

<u>Partial pressure of hydrogen = 189 torr.</u>
<u>Answer:</u> The isomers are shown in the image below.
<u>Explanation:</u>
Isomers are defined as the chemical compounds having the same number and kinds of atoms but arrangement are different.
For the alkane having four carbon atoms and 1 bromine atom, the IUPAC name of the haloalkane is bromobutane
There are 4 possible isomers for the given haloalkane compound:
- 1-bromobutane
- 2-bromobutane
- 1-bromo-2-methylpropane
- 2-bromo-2-methylpropane
The isomers of the given organic compound is shown in the image below.