Answer:
The dynamic viscosity of the liquid is 0.727 kg/m*s
Explanation:
In the equation for that viscosimeter, ν = KR⁴t, <u>the terms K and R are not dependent on the liquid that is being tested</u>, unlike ν and t.
Using that equation and the data given in the problem, we can calculate the product of K and R⁴.
1.19*10⁻³m²/s = (KR⁴)* 1430 s
KR⁴=8,32*10⁻⁷m²/s²
We can now calculate the<em> </em><u><em>kinematic</em></u> viscosity of the unknown liquid.
ν=8,32*10⁻⁷m²/s²*900s
ν=7.49*10⁻⁴m²/s
The relationship between the <em>kinematic</em> viscosity and the <em>dynamic</em> viscosity is given by the equation μ=ν * ρ, where μ is the dynamic viscosity and ρ is the density. Thus:
μ=7.49*10⁻⁴m²/s * 970 kg/m³
μ=0.727 kg/m*s
<span>Mn's
atomic number is 25 so you have 25 protons and 25 electrons in a
neutral atom. Since no charge is shown, the number of electrons is 25
Ni's atomic number is 28 so you have 28 protons and 28 electrons in a
neutral atom. This one shows a +3 so there are 3 missing electrons, the
number of electrons is 28 - 3 = 25
Cu's atomic number is 29 so you have 29 protons and 29 electrons in a
neutral atom. This one shows a +2 so there are 2 missing electrons, the
number of electrons is 29 - 2 = 27
Ti's atomic number is 22 so you have 22 protons and 22 electrons in a
neutral atom. This one shows a -2 so there are 2 EXTRA electrons, the
number of electrons is 22 + 2 = 24 </span>
The kind of energy released when atoms are rearranged to form new bonds is called Chemical energy.
Answer:
Júpiter and 60000 the are the awnsers
