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2 years ago

How many moles are in 79.85g Fe2O3?

Chemistry

2 answers:

strojnjashka [21]2 years ago

8 0

Answer:

in 79.85 g of Fe2O3 there will be 0.5 moles of Fe2O3

Explanation:

To find the number of moles we must calculate the molecular weight of iron oxide, for that we use the periodic table:

mFe = 55.845 g/mol

mO = 15.999 g/mol

mFe2O3 = (2x55.845) + (3x15.999) = 159.687 g/mol

1 mole of iron oxide weighs 159.687 g, therefore, to calculate the number of moles present in 79.85 g it will be equal to:

nFe2O3 = 79.85/159.687 = 0.5 moles

mamaluj [8]2 years ago

4 0

<span>Find molar mass of Fe2O3 = 159.7 g/mol
Then: 79.85g/159.7 g/mol = 0.5 mol</span>

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corrected question: A chemist adds 135mL of a 0.21M zinc nitrate solution to a reaction flask. Calculate the mass in grams of zinc nitrate the chemist has added to the flask. Round your answer to significant digits.

Answer:

5.37g

Explanation:

0.21M means ; 0.21mol/dm³

1dm³=1L , so we can say 0.21mol/L

if 0.21mol of Zinc nitrate is contained in 1L of water

x will be contained in 135mL of water

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2 years ago

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2 years ago

How do the first ionization energies of main group elements vary across a period and down a group?

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3 years ago

When 0.0901 mol of an unknown hydrocarbon is burned in a bomb calorimeter, the calorimeter increases in temperature by 2.19°C. I

Alexus [3.1K]

Answer:

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Explanation:

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3 years ago

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How would you prepare 1.00 L of a 0.400M solution of copper(II)sulfate, CuSO4?

Ber [7]

We need to dilute 0.400 mol of copper (II) sulfate, how do we know, how many weigh of $CuSO_4$ we have to dilute??

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2 years ago

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