Answer:
Power will be 0.2023 watt
And when amplitude is halved then power will be 0.0505 watt
Explanation:
We have given mass of the Piano wire m = 2.60 gram = 0.0026 kg
Length of wire l = 84 cm = 0.84 m
So mass density 
Tension in the wire T = 25 N
Frequency f = 120 Hz
So angular frequency 
And amplitude A = 1.6 mm = 0.0016 m
We have to find the generated power
Power is given by 
From the relation we can see that power 
So if amplitude is halved then power will be 
times
So power will be equal to 
Answer:
The answer is "-72 k".
Explanation:
Please find the complete question in the attached file.
Given point:
Calculating the area:
![=i[8(0)-8(0)]-j[(0-0)]+k[(0-9(8))]\\\\=i[0-0]-j[(0)]+k[(0-72)]\\\\=i[0]-j[(0)]+k[(-72)]\\\\=-72 \ k](https://tex.z-dn.net/?f=%3Di%5B8%280%29-8%280%29%5D-j%5B%280-0%29%5D%2Bk%5B%280-9%288%29%29%5D%5C%5C%5C%5C%3Di%5B0-0%5D-j%5B%280%29%5D%2Bk%5B%280-72%29%5D%5C%5C%5C%5C%3Di%5B0%5D-j%5B%280%29%5D%2Bk%5B%28-72%29%5D%5C%5C%5C%5C%3D-72%20%5C%20k)
There are two<span> main types of </span>wave<span> interference: constructive interference and destructive interference. Constructive interference </span>happens<span> when the amplitude of the combined </span>waves<span> is larger than the amplitudes of the single </span>waves<span>. This can occur when the </span>crests of two<span> transverse </span><span>waves overlap.
Hope this helps!!! :D
</span>
The Kelvin scale is also called absolute zero scale
Explanation:
true
Answer:
No
Explanation:
You could try to give it enough to fill all valence electrons in all of the atoms in the conductor, but practically this could not be achieved.
