Question seems to be missing. Found it on google:
a) How long is the ski jumper airborne?
b) Where does the ski jumper land on the incline?
a) 4.15 s
We start by noticing that:
- The horizontal motion of the skier is a uniform motion, with constant velocity
and the distance covered along the horizontal direction in a time t is
- The vertical motion of the skier is a uniformly accelerated motion, with initial velocity 
and constant acceleration 
(where we take the downward direction as positive direction). Therefore, the vertical distance covered in a time t is
The time t at which the skier lands is the time at which the skier reaches the incline, whose slope is
below the horizontal
This happens when:
Substituting and solving for t, we find:
b) 143.6 m
Here we want to find the distance covered along the slope of the incline, so we need to find the horizontal and vertical components of the displacement first:
The distance covered along the slope is just the magnitude of the resultant displacement, so we can use Pythagorean's theorem:
Answer:
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Drift velocity- the average speed at which these charges move
D. All of the above
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Explanation:
