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77julia77 [94]
3 years ago
5

Describe how the earth this place density satisfaction in your answer discussed internally yours of the earth and

Physics
1 answer:
EastWind [94]3 years ago
5 0
And..............I dont think you wrote the whole question
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Why are frames of reference important for motion
Fynjy0 [20]
Because frame of reference decides are your forces positive or negative. It is important for the direction of motion.
7 0
3 years ago
Suppose you are asked to find the amount of time t, in seconds, it takes for the turntable to reach its final rotational speed.
Annette [7]

Answer:

option (D)

Explanation:

Here initial rotation speed is given, final rotation speed is given and asking for time.

If we use

A) θ=θ0+ω0t+(1/2)αt2

For this equation, we don't have any information about the value of angular displacement and angular acceleration, so it is not useful.

B) ω=ω0+αt

For this equation, we don't have any information about angular acceleration, so it is not useful.

C) ω2=ω02+2α(θ−θ0)

In this equation, time is not included, so it is not useful.

D) So, more information is needed.

Thus, option (D) is true.

5 0
3 years ago
The narrator of a story
34kurt
The answer is d! I’m happy to help :)
7 0
3 years ago
Read 2 more answers
A train travels 1000 m south for 100 s. What is the
Alexandra [31]
C. 10 m/s
You divide 1000 m by 100 s.
1000/100 to find the velocity
5 0
3 years ago
A 100-kg tackler moving at a speed of 2.6 m/s meets head-on (and holds on to) an 92-kg halfback moving at a speed of 5.0 m/s. Pa
DIA [1.3K]

Given that,

Mass of trackler, m₁ = 100 kg

Speed of trackler, u₁ = 2.6 m/s

Mass of halfback, m₂ = 92 kg

Speed of halfback, u₂ = -5 m/s (direction is opposite)

To find,

Mutual speed immediately after the collision.

Solution,

The momentum of the system remains conserved in this case. Let v is the mutual speed after the collision. Using conservation of momentum as :

m_1u_1+m_2u_2=(m_1+m_2)V\\\\V=\dfrac{m_1u_1+m_2u_2}{(m_1+m_2)}\\\\V=\dfrac{100\times 2.6+92\times (-5)}{(100+92)}\\\\V=-1.04\ m/s

So, the mutual speed immediately after the collision is 1.04 m/s but in opposite direction.

3 0
3 years ago
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