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Anestetic [448]
3 years ago
7

A wave carries _____ from one place to another Mechanical waves carry energy through ______

Physics
2 answers:
gulaghasi [49]3 years ago
7 0

A wave carries <u>energy</u><u> </u>from one place to another.

mechanical waves carry energy through <u>MEDIUM</u><u>.</u>

<u>SO</u><u> </u><u>THIS</u><u> </u><u>IS</u><u> </u><u>MY</u><u> </u><u>ANSWER</u>

antiseptic1488 [7]3 years ago
5 0

Answer:

Energy

Matter

Explanation:

Bcuz I just did it on the warm up for edge

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yaroslaw [1]
"<span>a layer in the earth's stratosphere at an altitude of about 6.2 miles (10 km) containing a high concentration of ozone, which absorbs most of the ultraviolet radiation reaching the earth from the sun."

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4 0
3 years ago
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How much energy is stored in a 2.80-cm-diameter, 14.0-cm-long solenoid that has 200 turns of wire and carries a current of 0.800
ozzi

Answer:

The energy stored in the solenoid is 7.078 x 10⁻⁵ J

Explanation:

Given;

diameter of the solenoid, d = 2.80 cm

radius of the solenoid, r = d/2 = 1.4 cm

length of the solenoid, L = 14 cm = 0.14 m

number of turns, N = 200 turns

current in the solenoid, I = 0.8 A

The cross sectional area of the solenoid is given as;

A = \pi r^2\\\\A = \pi (0.014)^2\\\\A = 6.16*10^{-4} \ m^2

The inductance of the solenoid is given by;

L = \frac{\mu_0 N^2A}{l} \\\\L =  \frac{(4\pi*10^{-7})(200^2)(6.16*10^{-4})}{0.14}\\\\L = 2.212*10^{-4} \ H

The energy stored in the solenoid is given by;

E = ¹/₂LI²

E = ¹/₂(2.212 x 10⁻⁴)(0.8)²

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8 0
3 years ago
A 975-kg sports car (including driver) crosses the rounded top of a hill at determine (a) the normal force exerted by the road o
iVinArrow [24]
There are missing data in the text of the problem (found them on internet):
- speed of the car at the top of the hill: v=15 m/s
- radius of the hill: r=100 m

Solution:

(a) The car is moving by circular motion. There are two forces acting on the car: the weight of the car W=mg (downwards) and the normal force N exerted by the road (upwards). The resultant of these two forces is equal to the centripetal force, m \frac{v^2}{r}, so we can write:
mg-N=m \frac{v^2}{r} (1)
By rearranging the equation and substituting the numbers, we find N:
N=mg-m \frac{v^2}{r}=(975 kg)(9.81 m/s^2)-(975 kg) \frac{(15 m/s)^2}{100 m}=7371 N

(b) The problem is exactly identical to step (a), but this time we have to use the mass of the driver instead of the mass of the car. Therefore, we find:
N=mg-m \frac{v^2}{r}=(62 kg)(9.81 m/s^2)-(62 kg) \frac{(15 m/s)^2}{100 m}=469 N

(c) To find the car speed at which the normal force is zero, we can just require N=0 in eq.(1). and the equation becomes:
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7 0
4 years ago
Why is force not on a scalar quantity??
snow_lady [41]
Because force always has a direction, it always works towards or against something.


you might know that force,
is rate of change of momentum i.e

force = m (v-u)/t
= (mv - mu )/ t


as we know momentum is a vector quantity so, the rate of change of momentum i.e Force would also be a vector quantity.




momentum = mass × velocity

velocity has a direction so,
momentum has also got a direction.
so, momentum is also a vector quantity.
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balandron [24]
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it is like a pattern

hope that was helpful.</span>
3 0
3 years ago
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