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2 years ago

How does the "human" part of human resources influence how companies need to treat these resources?

Physics

1 answer:

kap26 [50]2 years ago

8 0

A. Companies should consider that people will learn more and become more valuable over time.

<h3>Importance of human resources</h3>

human resources provide the organization with a clear vision of competitive advantage and contribute affectively to the organizational success in general.

Human resources also ensure employee satisfaction.

Thu, "human" part of human resources influence how companies need to treat these resources by ensuring that companies consider that people will learn more and become more valuable over time.

Learn more about human resources here: brainly.com/question/10583893

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Two wires A and B with circular cross-section are made of the same metal and have equal lengths, but the resistance of wire A is

Nesterboy [21]

Answer:

r₁/r₂ = 1/2 = 0.5

Explanation:

The resistance of a wire is given by the following formula:

R = ρL/A

where,

R = Resistance of wire

ρ = resistivity of the material of wire

L = Length of wire

A = Cross-sectional area of wire = πr²

r = radius of wire

Therefore,

R = ρL/πr²

<u>FOR WIRE A</u>:

R₁ = ρ₁L₁/πr₁² -------- equation 1

<u>FOR WIRE B</u>:

R₂ = ρ₂L₂/πr₂² -------- equation 2

It is given that resistance of wire A is four times greater than the resistance of wire B.

R₁ = 4 R₂

using values from equation 1 and equation 2:

ρ₁L₁/πr₁² = 4ρ₂L₂/πr₂²

since, the material and length of both wires are same.

ρ₁ = ρ₂ = ρ

L₁ = L₂ = L

Therefore,

ρL/πr₁² = 4ρL/πr₂²

1/r₁² = 4/r₂²

r₁²/r₂² = 1/4

taking square root on both sides:

6 0

4 years ago

Can someone please help me ASAP???!!!

olganol [36]

Answer: The answers are:

Explanation:

1. C

2. A

3. C

4. B

5. D

8 0

2 years ago

How does the law of conservation of matter apply to chemical equations? A. The sum of the coefficients on each side of the equat

irinina [24]

The answer is letter D.

5 0

3 years ago

Read 2 more answers

4. What's the voltage drop if V, = 56 V, V2 = 35 V, and V3 = 3 V

Murrr4er [49]

Answer:

The correct option is A. 18 V

Therefore,

$V_{1}=18\ V$

Explanation:

Given:

Total Voltage,

V = 56 V,

Voltage drop

$V_{2}=35\ V$

$V_{3}=3\ V$

To Find:

$V_{1}=?$ (Assumed ,as it is not given clearly in the question)

Solution:

So in series combination total Voltage is given as

$V=V_{1}+V_{2}+V_{3}$

Substituting the values we get

$56=V_{1}+35+3\\\\V_{1}=56-38=18\ V$

Therefore,

$V_{1}=18\ V$

5 0

3 years ago

A 2.0-kg cart collides with a 1.0-kg cart that is initially at rest on a low-friction track. After the collision, the 1.0-kg car

nikitadnepr [17]

To solve this problem we will apply the concepts related to the conservation of momentum. The momentum can be defined as the product between the mass of the object and its velocity, and the conservation of the momentum as the equality between the change of the initial momentum versus the final momentum. Mathematically, this relationship can be described as

$m_1u_1+m_2u_2 = m_1v_2+m_2v_2$

Here,

$m_{1,2}$ = Mass of each object

$u_{1,2}$ = Initial velocity of each object

$v_{1,2}$ = Final velocity of each object

According to the statement one of the bodies does not have initial velocity, therefore said term would be zero. And the equation could be rewritten as,

$m_1u_1= m_1v_2+m_2v_2$

Replacing the values respectively (The mass of your body with its respective speed we would have)

$2kg(u_1) = 2kg(0.3m/s)+1kg(0.5m/s)$

$u_1 = \frac{2kg(0.3m/s)+1kg(0.5m/s)}{2kg}$

$u_1 = 0.55m/s$

Therefore the initial velocity of the 2kg cart is 0.55m/s

4 0

3 years ago