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2 years ago

How does the "human" part of human resources influence how companies need to treat these resources?

Physics

1 answer:

kap26 [50]2 years ago

8 0

A. Companies should consider that people will learn more and become more valuable over time.

<h3>Importance of human resources</h3>

human resources provide the organization with a clear vision of competitive advantage and contribute affectively to the organizational success in general.

Human resources also ensure employee satisfaction.

Thu, "human" part of human resources influence how companies need to treat these resources by ensuring that companies consider that people will learn more and become more valuable over time.

Learn more about human resources here: brainly.com/question/10583893

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5. Alex goes cruising on his dirt bike. He rides 700 m north, 300 m east, 400 m north, 600 m west, 1200 m south 300 m east and f

Gala2k [10]

Answer:

Explanation:

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5 0

3 years ago

Find the currents flowing in the circuit in the figure below. (Assume the resistances are

Nitella [24]

By Kirchoff's law in left side loop

$E_1 + E_2 = {r_1 + R_1 + R_4)I_1 + (R_2 + r_2) I_3$

similarly kirchoff's law in right side loop

$E_3 - E_4 - E_2 = (r_3 + r_4 + R_3)I_2 - (R_2 + r_2)I_3$

also by junction law we know that

$I_1 = I_2 + I_3$

now by plug in all values we have

$18 + 3 = (0.5 + 8 + 15)I_1 + (10 + 0.25)I_3$

$21 = 23.5I_1 + 10.25I_3$

$12 - 24 - 3 = (0.75 + 0.25 + 12)I_2 - (10+ 0.25)I_3$

$-15 = 13I_2 - 10.25I_3$

So by solving above equations we have

$I_1 = 0.492 A$

$I_2 = -0.428 A$

$I_3 = 0.920 A$

6 0

4 years ago

A ball tossed vertically upward from the ground next to a building passes the bottom of a window 1.8 s after being tossed and pa

VLD [36.1K]

The ball takes 0.2 sec to travel the height of the window, which is 2 m.

Then the speed of the ball at that time was

$v = \frac{d}{t}$

$v = \frac{2}{0.20}$

$v = 10\ \frac{m}{s}$

We know that:

$v = v_0 -gt$

Where $v_0$ is the initial velocity.

So:

$10 = v_0 -9.8(2)$

$10 + 9.8(2) = v_0$

$v_0 = 29.6\ m / s$

Then we have the equation for the position as a function of time.

$r = r_0 + v_0t - \frac{1}{2}gt^2$

Where

$r_0$ = initial position

r = position as a function of time

$v_0$ = initial velocity

g = acceleration of gravity

t = time.

If the ball is thrown from the ground then:

$r_0$ = 0 m

We want to find now the distance between the window and the ground.

When the ball reaches the bottom of the window t = 1.8s

So:

$r = 0 + 29.6(1.8) - 0.5(9.8)(1.8)^2$

$r = 37,404$ m

The window is 37,404 m high

Finally, to know how high the ball rises we must know at what moment the vertical velocity of the ball is zero.

$v = v_0 -gt\\\\0 = v_0 -gt\\\\gt = v_0\\\\t = \frac{29.6}{9.8}$

$t = 3.02\ s$

Now we replace t in the position equation

$r = 0 + 29.6(3.02) -0.5(9.8)(3.02)^2$

$r = 44.70\ m$

The ball reaches up to 44.70 m in height.

3 0

3 years ago

A teacher lifted a 10 N box and placed it down. Did she do any work? Explain your answer using math

Stells [14]

Answer:

i think it is 45 kilograms not really sure?

Explanation:it might be wrong but i think it is right

8 0

3 years ago

Due to design changes, the efficiency of an engine increases from 0.28 to 0.51. For the same input heat |QH|, these changes incr

Volgvan

Answer:

the ratio of the heat rejected to the cold reservoir for the improved engine to that for the original engine is 0.68

Explanation:

Given information

initial efficiency, η $_{1}$ = 0.28

final efficiency, η $_{2}$ = 0.51

ratio of the heat rejected = (1 - η $_{2}$ )/(1 - η $_{1}$ )

= (1 - 0.51)/(1 - 0.28)

= 0.68

4 0

3 years ago