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umka2103 [35]
2 years ago
8

A 102 kg box is pushed on a linoleum floor with an acceleration of 2.5 ms to the second power. The force of the kinetic movie fr

iction between the box in the floor is 42 N. What is the net force acting on the box.
Physics
1 answer:
maria [59]2 years ago
8 0

A force is the push or pull acting on an object as a result of its interaction with another object. Here the net force acting on the box is 297 N

From the question

Given that,  

Mass of the box ,m = 102 kg

Acceleration of the box ,a = 2.5 m/s²

Frictional force acting between the box and the floor ,<em>f =</em> 42 N

Here we have to find the net force acting on the body, F = ?

By Newton's second law of motion,

∑F = ma,

where, F is the net force

m is the mass of the body

a is the acceleration of the moving body

If the body is considered moving in the x-direction then,

F-<em>f = ma</em>

<em>F - 42 = 102 x 2.5</em>

<em>          = 255</em>

<em>F = 255 + 42 = 297 N </em>

To learn more about force : brainly.com/question/12800231

#SPJ1

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The time required for light to travel in one year.

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A bullet is fired into the air at an angle of 30° to the horizontal. At the same time and from the same height,
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4 0
4 years ago
A student on a tower 49 m height drops a stone. One second later he throws a second stone after the first. They both hit the gro
ohaa [14]

By applying the second equation of motion, the speed at which he threw the second stone is equal to 12.10 m/s.

<h3>How to determine the speed?</h3>

First of all, we would calculate the time taken by the first stone to reach a height of 49 meters by applying the second equation of motion as follows:

S = ut + ½gt²

49 = 0(t) + ½ × 9.8 × t²

49 = 4.9t²

t² = 49/4.9

t = √10

t = 3.16 seconds.

Now, we can determine the speed at which he threw the second stone:

<u>Note:</u> Time = 3.16 - 1 = 2.16 seconds.

S = ut + ½gt²

49 = u(2.16) + ½ × 9.8 × 2.16²

49 = 2.16u + 22.86

2.16u = 49 - 22.86

u = 26.14/2.16

u = 12.10 m/s.

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6 0
2 years ago
A 3 inch fire hose has a water flow of 200 gallons per minute. What is the flow in liters per second? Note: Use US gallons not U
stepladder [879]

Answer:

Case I: 12.617 L/s

Case II: 161.406 cubic meters per hour

Case III: 1.062 Pound inches

Explanation:

<u>Given:</u>

  • Speed of water flow = 200 gallons per minute
  • Speed of air blow = 95 cubic feet per minute
  • Measure of Torque = 12 Newton centimeter

<u>Assumptions:</u>

  • 1 US gallon = 3.785 L
  • 1 min = 60 s
  • 1 ft = 0.3048 m
  • 1 h = 60 min
  • 1 inch = 2.54 cm
  • 1 N = 0.2248 lb

Case I:

Speed\ of\ water\ flow = 200 \dfrac{gallon}{min}\\\Rightarrow V_{water} = 200\times \dfrac{3.785\ L}{60\ s}\\\Rightarrow V_{water} = 12.617\ L/s

Case II:

Speed\ of\ air\ blow = 95 \dfrac{ft^3}{min}\\\Rightarrow V_{air} = 95\times \dfrac{(0.3048\ m)^3}{\dfrac{1}{60}\ h}\\\Rightarrow V_{air} = 95\times (0.3048)^3\times 60\ m^3/h\\\Rightarrow V_{air} = 161.406\ m^3/h

Case III:

Measure\ of\ torque = 12\ N cm\\\Rightarrow \tau = 12\times (0.2248\ lb)\times \dfrac{1}{2.54}\ in\\ \Rightarrow \tau = 1.062\ lb in

6 0
3 years ago
7. An engineer is using a wire that has a resistance of 1.5 . This resistance is too high for the application he is designing. T
Veronika [31]

Answer and Explanation:

We know that resistance R=\frac{\rho l}{A}  from the given equation of resistance it is clear that resistance depends on resistivity length  and area of the material but we can not change the length because it is given that the length must be 2.5 cm long.

So we can do two two things to reduce the resistance

  1. increase the cross sectional area
  2. decrease the resistivity of the material
7 0
3 years ago
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