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2 years ago

Choose the stronger acid in each of the following pairs:H₃PO₄ or H₃AsO₄

Chemistry

1 answer:

patriot [66]2 years ago

6 0

H₃PO₄ is stronger acid than H₃AsO₄.

H₃PO₄ is the stronger acid because PO₄is more electronegative than Se so PO₄3- is more stable than AsO₄3-.

<h3>Acid definition</h3>

Any substance that tastes sour in water solution, turns blue litmus paper red, reacts with some metals to release hydrogen, reacts with bases to form salts, and stimulates chemical reactions is considered an acid (acid catalysis).

An acid is a chemical substance, typically a liquid, that contains hydrogen and can interact with other substances to form salts. Some acids react with other materials and burn or dissolve them.

Acids are frequently encountered in daily life. They exist naturally in foods, are found in cells and digestive systems, and are used in numerous regular chemical reactions. Strong acids that are frequently used include nitric acid, phosphoric acid, sulfuric acid, and hydrochloric acid.

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Fill in the coefficients that will balance the following reaction:

Burka [1]

Answer:

a0 = 2

a1= 9

a2= 6

a3= 8

Explanation:

The equation for the reaction is;

C3H7OH + O2 → CO2 + H2O

To balance the chemical equation we introduce coefficients;

Therefore the balanced chemical equation will be;

2C3H7OH + 9O2 → 6CO2 + 8H2O

Chemical equations are balanced to ensure the law of conservation of mass is obeyed, such that the mass of the reactants is equivalent to that of the products.

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3 years ago

Explain the Anchoring Phenomenon (summary)

Virty [35]

An anchoring phenomenon anchors all of the learning within a unit. So, it is a unit level event that the classroom is trying to make sense of as they engage in a series of lessons.

Since the questions the students ask about the anchor drive the learning within the unit, the anchor should be complex and require an understanding of several big science ideas to explain.

At strategic moments, the class revisits the anchoring phenomenon to review their initial questions to see which they have answered, which they are making progress on, and what new questions they may have to help us continue learning about the phenomenon.

Throughout the unit, the classroom and each student should be given opportunities to share their thinking and how it relates to the anchoring phenomenon.
YOU SHOULD PUT IT IN YOUR OWN WORDS THOUGH <3

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3 years ago

What order must the earth, the sun, and the moon be in to be a lunar eclipse?

zhannawk [14.2K]

A total lunar eclipse takes place when the Earth comes between the Sun and the Moon and covers the Moon with its shadow. When this happens, the Moon can turn red, earning it the nickname of Blood Moon.

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3 years ago

What happens when magnesium reacts with iodine to make magnesium iodide?

I am Lyosha [343]

Explanation:

Atomic number of magnesium is 12 and its electronic distribution is 2, 8, 2. On the other hand, atomic number of iodine is 53 and its electronic configuration is $[Kr]4d^{10}5s^{2}5p^{5}$ .

Hence, there are 7 valence electrons in an iodine atom and there are 2 valence electrons in a magnesium atom.

So, one atom of iodine requires one electron from a donor atom to complete its octet. But one magnesium atom contains two valence electrons.

Therefore, one magnesium atom will combine with two iodine atoms to result in the formation of magnesium iodide as follows.

$Mg^{2+} + 2I^{-} \rightarrow MgI_{2}$

Therefore, an ionic bond will be formed when magnesium reacts with iodine to make magnesium iodide.

7 0

4 years ago

The enthalpy of solution (∆H) of KOH is -57.6 kJ/mol. If 3.66 g KOH is dissolved in enough water to make a 150.0 mL solution, wh

Wewaii [24]

When 3.66 g of KOH (∆Hsol = -57.6 kJ/mol) is dissolved in 150.0 mL of solution, it causes a temperature change of 5.87 °C.

The enthalpy of solution of KOH is -57.6 kJ/mol. We can calculate the heat released by the solution (Qr) of 3.66 g of KOH considering that the molar mass of KOH is 56.11 g/mol.

$3.66g \times \frac{1mol}{56.11g} \times \frac{(-57.6kJ)}{mol} = -3.76 kJ$

According to the law of conservation of energy, the sum of the heat released by the solution of KOH (Qr) and the heat absorbed by the solution (Qa) is zero.

$Qr+Qa = 0\\\\Qa = -Qr = 3.76 kJ$

150.0 mL of solution with a density of 1.02 g/mL were prepared. The mass (m) of the solution is:

$150.0 mL \times \frac{1.02g}{mL} = 153 g$

Given the specific heat capacity of the solution (c) is 4.184 J/g･°C, we can calculate the change in the temperature (ΔT) of the solution using the following expression.

$Qa = c \times m \times \Delta T\\\\\Delta T = \frac{Qa}{c \times m} = \frac{3.76 \times 10^{3}J }{\frac{4.184J}{g.\° C } \times 153g} = 5.87 \° C$

When 3.66 g of KOH (∆Hsol = -57.6 kJ/mol) is dissolved in 150.0 mL of solution, it causes a temperature change of 5.87 °C.

Learn more: brainly.com/question/4400908

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2 years ago