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Lynna [10]
2 years ago
11

Choose the stronger acid in each of the following pairs:H₃PO₄ or H₃AsO₄

Chemistry
1 answer:
patriot [66]2 years ago
6 0

H₃PO₄ is stronger acid than H₃AsO₄.

H₃PO₄ is the stronger acid because PO₄is more electronegative than Se so PO₄3- is more stable than AsO₄3-.

<h3>Acid definition</h3>

Any substance that tastes sour in water solution, turns blue litmus paper red, reacts with some metals to release hydrogen, reacts with bases to form salts, and stimulates chemical reactions is considered an acid (acid catalysis).

An acid is a chemical substance, typically a liquid, that contains hydrogen and can interact with other substances to form salts. Some acids react with other materials and burn or dissolve them.

Acids are frequently encountered in daily life. They exist naturally in foods, are found in cells and digestive systems, and are used in numerous regular chemical reactions. Strong acids that are frequently used include nitric acid, phosphoric acid, sulfuric acid, and hydrochloric acid.

To learn more about acid visit:

brainly.com/question/14072179

#SPJ4

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Help me please I really do need help pls text me if u wanna help me more
8090 [49]
Respiration . I’m pretty sure
8 0
3 years ago
How many liters of a 3 M NaOH stock solution would you need to make 552 mL of a 105 mM NaOH dilution
Ganezh [65]

Answer:

0.01932 L

Explanation:

First we <u>convert 105 mM to M</u>:

  • 105 mM / 1000 = 0.105 M

Next we <u>convert 552 mL to L</u>:

  • 552 mL / 1000 = 0.552 L

Then we use the following equation:

  • C₁V₁=C₂V₂

Where:

  • C₁ = 3 M
  • V₁ = ?
  • C₂ = 0.105 M
  • V₂ = 0.552 L

We<u> input the given data</u>:

  • 3 M * V₁ = 0.105 M * 0.552 L

And <u>solve for V₁</u>:

  • V₁ = 0.01932 L
7 0
3 years ago
Which type of reaction occurs when 50mL quantities of 1 M Ba(OH)2 (aq) and H2SO4 (aq) are combined
iragen [17]
Double replacement.

Ba(OH)2 + H2SO4 ====> 2H2O + BaSO4
5 0
4 years ago
Which member of each pair is more soluble in water? Why?<br> (a) CH₃CH₂OCH₂CH₃(l) or CH₃CH₂OCH₂(g)
Anna [14]

CH₃CH₂OCH₂ is more soluble in water because it has shorter hydrocarbon chain.

<h3>What is hydrocarbon?</h3>

Hydrocarbon is defined as the compound which contain hydrocarbon and carbon atoms.

The carbon atom attached to each other to form framework and hydrogen atom attach to them in different ways to give different configuration. One of the most popular hydrocarbon compound is diamond.

<h3>Solubility of hydrocarbon in water</h3>

Hydrocarbon is non polar compound whereas water is polar compound. So, hydrocarbon is in soluble in water. But as they have weak intermolecular interactions known as London dispersion forces i.e. Instantaneous dipole-induced dipole interactions.

make them less soluble in water.

Greater the hydrocarbon chain lesser will be the solubility of ketone in water. On the other hand, lesser the hydrocarbon chain greater will be the solubility of ketone in water.

Thus, we concluded that the CH₃CH₂OCH₂ is more soluble in water because it has shorter hydrocarbon chain.

learn more about hydrocarbon:

brainly.com/question/16020705

#SPJ4

7 0
2 years ago
Does it take more, less, or the same amount of heat to melt 1.0 kg of ice at 0°C, or to bring 1.0 kg of liquid water at 0°C to t
Murljashka [212]

Answer : It takes less amount of heat to metal 1.0 Kg of ice.

Solution :

The process involved in this problem are :

(1):H_2O(s)(0^oC)\rightarrow H_2O(l)(0^oC)\\\\(2):H_2O(l)(0^oC)\rightarrow H_2O(l)(100^oC)

Now we have to calculate the amount of heat released or absorbed in both processes.

<u>For process 1 :</u>

Q_1=m\times \Delta H_{fusion}

where,

Q_1 = amount of heat absorbed = ?

m = mass of water or ice = 1.0 Kg

\Delta H_{fusion} = enthalpy change for fusion = 3.35\times 10^5J/Kg

Now put all the given values in Q_1, we get:

Q_1=1.0Kg\times 3.35\times 10^5J/Kg=3.35\times 10^5J

<u>For process 2 :</u>

Q_2=m\times c_{p,l}\times (T_{final}-T_{initial})

where,

Q_2 = amount of heat absorbed = ?

m = mass of water = 1.0 Kg

c_{p,l} = specific heat of liquid water = 4186J/Kg^oC

T_1 = initial temperature = 0^oC

T_2 = final temperature = 100^oC

Now put all the given values in Q_2, we get:

Q_2=1.0Kg\times 4186J/Kg^oC\times (100-0)^oC

Q_2=4.186\times 10^5J

From this we conclude that, Q_1 that means it takes less amount of heat to metal 1.0 Kg of ice.

Hence, the it takes less amount of heat to metal 1.0 Kg of ice.

5 0
3 years ago
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