2Cu(s) + O2(g) --> 2CuO(s)
Answer:
The correct answer is 5.0 L
Explanation:
STP are defined as T=273 K and P= 1 atm
By using the ideal gas equation, we can calculate the number of moles (n) of the gas at a volume V=2.5 L:
PV= nRT
⇒n= (PV)/(RT) =(1 atm x 2,5 L)/(0.082 L.atm/K.mol x 273 K)= 0.112 mol
For a sample of argon gas, with the same number of moles (0.112 mol) but twice the temperature (T = 273 K x 2= 546 K):
V= (nRT)/P = (0.112 mol x 0.082 L.atm/K.mol x 546 K)/1 atm = 5.0 L
That is consistent with the fact that when a gas is heated, it expanses. So, if the temperature increases twice, the volume also increases twice.
Answer:
20.11 g.
Explanation:
What is given?
c (specific heat of iron) = 0.450 J/g °C.
Q (heat energy) = 179.85 J.
ΔT (change of temperature) = |31.42 °C - 51.29 °C| = 19.87 °C.
What do we need? Mass of iron (m)
Step-by-step solution:
Let's see the formula of specific heat:
Where c is specific heat, Q is heat energy, m is mass and ΔT is the change of temperature.
We just have to solve for 'm' to find the mass of iron and replace the given data that we have, like this:
The mass of the iron would be 20.11 g.
Answer: malleable
explanation: malleable means to be easily manipulated in shape
Answer: 36.53g
Explanation:
First we need to find the amount of NaCl that dissolves in 1L of the solution that produced 5M of NaCl
Molarity = 5M
MM of NaCl = 58.45
Molarity = Mass conc (g/L) / MM
Mass conc. (g/L) of NaCl = Molarity x MM
= 5 x 58.45 = 292.25g
Next, we need to find the amount that will dissolve in 125mL(i.e 0.125L)
From the calculations above,
292.25g of NaCl dissolved in 1L
Therefore Xg of NaCl will dissolve in 0.125L of the solution i.e
Xg of NaCl = 292.25 x 0.125 = 36.53g.
Therefore 36.53g of NaCl will dissolve in 125mL of the solution
