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zheka24 [161]
1 year ago
11

A man runs at an average speed of 5.0m/s how long will it take him to run 5.2km on a perfectly straight line

Physics
1 answer:
Anni [7]1 year ago
8 0

The time taken is 1040 s.

<h3>What is speed?</h3>

The term speed refers to the rate at which the distance changes per unit time. This is why we define speed as the ratio of the distance to time for a body that is moving along a straight line.

Now;

We must first convert the distance to meters;

distance = 5.2km  or 5200m

Speed = distance/time

time = distance/speed

time =  5200m/5 m/s

time = 1040 s

Learn more about speed:brainly.com/question/28224010

#SPJ1

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The normal force equals the magnitude of the gravitational force as a roller coaster car crosses the top of a 58-m-diameter loop
dedylja [7]

Answer:

16.87 m/s

Explanation:

To find the speed of the car at the top, when the normal force is equal the gravitational force, we just need to equate both forces:

N = P

m*a_c = mg

a_c is the centripetal acceleration in the loop:

a_c = v^2/r

So we have that:

mv^2/r = mg

v^2/r = g

v^2 = gr

v = \sqrt{gr}

So, using the gravity = 9.81 m/s^2 and the radius = 29 meters, we have:

v = \sqrt{9.81 * 29}

v = \sqrt{284.49} = 16.87\ m/s

The speed of the car is 16.87 m/s at the top.

5 0
3 years ago
I'll give brainliest if you give me a good awnser. :)
lbvjy [14]

Answer:

0.5

Explanation:

4 0
3 years ago
Read 2 more answers
A tightrope walker wants to know the tension used to support the rope that is suspended between two poles. The rope is 18 m long
Alla [95]

Answer:

T = 29.6 N

Explanation:

length of the rope is

L = 18 m

mass of the rope is

m = 12 kg

now we have

mass per unit length of the rope is given as

[te]\lambda = \frac{12 kg}{18 m}[/tex]

now time taken by wave to reach from end to other

t = \frac{L}{v}

2.7 s = \frac{18}{v}

v = 6.67 m/s

now we have

v = \sqrt{\frac{T}{\lambda}}

6.67 = \sqrt{\frac{T}{0.67}}

so we will have

T = 29.6 N

5 0
4 years ago
an object 5 cm in size is placed at 30 cm in front of a concave mirror of focal length 45 CM at what distance from the mirror sh
Makovka662 [10]

Answer: Given: h₀=5cm

p=30cm

hi

f=45cm

require: q=?

hi=?

formulas:

1/f=1/p+1/q

hi/h₀=q/p

calculations:1/q=1/f-1/p

1/q=1/45-1/30

1/q=0.022=0.033

1/q=  =    -0.011

q=1/-0.011

q=   -90.91cm

hi=p × h₀/q

hi=30ₓ5/-90.91

hi=150/-90.91

hi= -1.65cm

image is virtual , erect and diminished

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3 0
3 years ago
1. Claim: Write a sentence stating whether texting and driving is potentially hazardous
My name is Ann [436]

Answer:

Texting and driving is potentially hazardous because it can cause death to yourself as well as someone else, car crashes, or run red lights and causing collisions.

Explanation:

3 0
3 years ago
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