Question

What is the change in internal energy (in J) of a system that absorbs 0.615 kJ of heat from its surroundings and has 0.247 kcal of work done on it?

Answer 1

The change in internal energy of a system is 1648.45 J.

First we convert calories into joule :-

From question, values are given q = 0.615 kJ

                                                     q  = 615 J

                                                  w = 0.247 kcal

                                                  w = 247 Cal = 247 × 4.184 J

                                                  w = 1033.45 J

Formula of change in internal energy, ΔE = q + w

Here, the system absorbs heat from surroundings, so q is positive

Now, put the values of q and w in the formula,

ΔE = q + w

ΔE = 615 + 1033.45 J

ΔE = 1648.45 J

Internal energy is the sum of ability power of the gadget and the machine's kinetic strength. The alternate in internal energy (ΔU) of a response is equal to the heat gained or lost (enthalpy trade) in a reaction whilst the reaction is administered at steady pressure. Inside the study of thermodynamics, a usually perfect gasoline is taken into consideration as a running substance. The molecules of an ideal gasoline are mere mass points that exert no force on each other.

The SI derived unit used to degree strength or paintings. One joule is identical to the electricity used to accelerate a body with a mass of 1 kilogram using one newton of force over a distance of one meter. One joule is also equal to one watt-second.

Learn more about internal energy here:- brainly.com/question/1370118

#SPJ4