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2 years ago

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1 answer:

Montano1993 [528]2 years ago

5 0

Commercial airliners encounter very little turbulence above 25,000 feet because the air is so thin at altitudes above 25,000 feet that turbulence has much less effect. That is option A.

<h3>What is turbulence?</h3>

A turbulence is a sudden disturbance that an airline encounters when it hits a strong wind current that can push or pull the plane.

The depth at which the airline flies determines whether the turbulence will have little or more effects on it.

At altitudes above 25,000 feet the air is so thin and light than below 25,000 feet therefore, the airline will encounter little turbulence effect.

Learn more about turbulence here:

brainly.com/question/20389242

#SPJ1

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his is a multi-part question. Once an answer is submitted, you will be unable to return to this part. Air enters a nozzle steadi

zepelin [54]

Answer:

his is a multi-part question. Once an answer is submitted, you will be unable to return to this part. Air enters a nozzle steadily at 2.21 kg/m3 and 40 m/s and leaves at 0.762 kg/m3 and 192 m/s. The inlet area of the nozzle is 90 cm2.

determine (a) the mass flow rate through the nozzle, and (b) the exit area of the nozzle.

a)0.7956kg/s

b)5.437 × 10⁻³m²

Explanation:

The concepts related to the change of mass flow for both entry and exit is applied

The general formula is defined by

$\dot{m}=\rho A V$

Where,

$\dot{m} = mass flow rate\\\rho = Density\\V = Velocity$

values are divided by inlet(1) and outlet(2) by

$\rho_1 = 2.21kg/m^3V_1 = 40m/s$

$A_1 = 90*10^{-4}m^2\\\rho_2 = 0.762kg/m^3\\V_2 = 192m/s$

PART A) Applying the flow equation

$\dot{m} = \rho_1 A_1 V_1\\\dot{m} = (2.21)(90*10^{-4})(40)\\\dot{m} = 0.7956kg/s$

PART B) For the exit area we need to arrange the equation in function of Area, that is

$A_2 = \frac{\dot{m}}{\rho_2 V_2}\\A_2 = \frac{0.7956}{(0.762)(192)}\\A_2 = 5.437*10^{-3}m^2$

7 0

3 years ago

Convert 15 litre into cubic metre

atroni [7]

Answer:

0.015m^3

Explanation:

1 m^3 = 1000 liters

x m^3 = 15 liters

Cross multiply

xm^3 x 1000 l = 15 l

Divide both sides by 1000

xm^3 x1000/1000 = 15/1000

xm^3 = 0.015m^3

Therefore 15 liter = 0.015m^3

5 0

3 years ago

What is the relationship between mass and inertia? Give an example

ad-work [718]

Mass is that quantity that is solely dependent upon the inertia of an object. The more inertia that an object has, the more mass that it ha

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3 years ago

What do the four terrestrial planets have in common?

stellarik [79]

They all have identical orbits shapes

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3 years ago

A celebrated Mark Twain story has motivated contestants in the Calaveras County Jumping Frog Jubilee, where frog jumps as long a

vladimir1956 [14]

Answer: x= 4.761 m/s

t=0.786 sec

Explanation: In a projectile motion (or 2D motion), the object is launched with an initial angle and an initial velocity

The components of the velocity are

<em>The magnitude, which is the speed, and the direction in which the motion is happening.</em>

Similarly the displacement has the components

The last formula is valid only if the object is launched at ground level, as our frog does.

There are two times where the value of y is zero, when t=0 (at launching time) and when it lands back from the air. We need to find that time t by making y=0

Dividing by t (assuming t different from zero)

Then we find the total flight as

Replacing this time in the formula of x

We can solve for

Knowing that x=2.20 m and °

We now compute t

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3 years ago