Ozone 03 have 2 sigma bond and 1 pie bond.
just remember this and you can do any problem for pie and sigma with this.
single bond = 1 sigma
double bond = 1 sigma and 1 pie
triple bond = 1 signa and 2 pie
I think the correct answer is b
Gas 2 because it has more particles that are colliding
Answer:
Using the Iodoform test, we can differentiate both compounds.
Explanation:
Benzaldehyde (C6H5CHO -an aldehyde) and Acetophenone (C6H5COCH3 - a methyl ketone) can be differentiated by reacting both compounds with iodine in a basic (NaOH) solutions.
The methyl ketone (acetophenone) gives a pale yellow precipitate of triiodomethane (iodoform) while the aldehyde (benzaldehyde) would not react.
This is known as the IODOFORM test and is indicative for methyl ketones
