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Evgen [1.6K]
1 year ago
14

1. To begin, check that this question is shown: The tallest building in the world, the Burj Khalifa

Chemistry
1 answer:
zimovet [89]1 year ago
5 0

Answer:

Explanation:

a. 82,000

b.Metric unit

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You have 0.21 moles of Al how many atoms do you have
ZanzabumX [31]

Number of atoms : 1.26 x 10²³

<h3>Further explanation  </h3>

The mole is the number of particles(molecules, atoms, ions) contained in a substance  

1 mol = 6.02.10²³ particles

Can be formulated

N=n x No

N = number of particles

n = mol

No = Avogadro's = 6.02.10²³

0.21 moles of Al, so n = 0.21

Number of atoms :

\tt N=0.21\times 6.02\times 10^{23}\\\\N=1.26\times 10^{23}

8 0
2 years ago
I build a fire and burn 3 logs. Apply the Law of Conservation of Matter
photoshop1234 [79]
Capture all of the smoke and weight it. it will weigh exactly the same before and after you burn it but will just be CO2 and H2O gas.
7 0
3 years ago
How many chlorine ions are required to bond with one aluminum ion
Monica [59]
The answer is Three
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4 0
3 years ago
What is the osmotic pressure of a solution made from 22.3 g of methanol (MM = 32.04 g/mol) that was added to water to make 321 m
xxMikexx [17]

Answer: The osmotic pressure of a solution is 53.05 atm

Explanation:

To calculate the concentration of solute, we use the equation for osmotic pressure, which is:

\pi=iMRT

Or,

\pi=i\times \frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}\times RT

where,

\pi = osmotic pressure of the solution = ?

i = Van't hoff factor = 1 (for non-electrolytes)

Mass of solute (methanol) = 22.3 g  

Volume of solution = 321 mL

R = Gas constant = 0.0821\text{ L.atm }mol^{-1}K^{-1}

T = temperature of the solution = 25^oC=[273+25]=298K

Putting values in above equation, we get:

\pi=1\times \frac{22.3\times 1000}{32.04\times 321}\times 0.0821\text{ L.atm }mol^{-1}K^{-1}\times 298K

\pi=53.05atm

Hence, the osmotic pressure of a solution is 53.05 atm

7 0
3 years ago
A single penny has a mass of 2.5 g. Abbie and James each measure the mass of a penny multiple times. Which statement about these
const2013 [10]
The question is missing the data sets.

This is the complete question:

A single penny has a mass of 2.5 g. Abbie and James each measure the mass of a penny multiple times. Which statement about these data sets is true? 

O Abbie's measurements are both more accurate and more precise than James'.

O Abbie's measurements are more accurate, but less precise, than James'. 

O Abbie's measurements are more precise, but less accurate, than James'. 

O Abbie’s measurements are both less accurate and less precise than James'. 

Penny masses (g)

Abbie’s data                                        

2.5, 2.4, 2.3, 2.4, 2.5, 2.6, 2.6 

James’ data


2.4, 3.0, 3.3, 2.2, 2.9, 3.8, 2.9

Answer: first option, Abbie's measurements are both more accurate and more precise than James'.

Explanation:


1) To answer this question, you first must understand the difference between precision and accuracy.

<span>Accuracy is how close the data are to the true or accepted value.
</span>

<span>Precision is how close are the data among them, this is the reproducibility of the values.</span>

Then, you can measure the accuracy by comparing the means (averages) with the actual mass of a penny 2.5 g.

And you measure the precision by comparing a measure of spread, as it can be the standard deviation.

2) These are the calculations:

Abbie’s data                      
                 
Average: ∑ of the values / number of values 

Average = [2.5 + 2.4 + 2.3 + 2.4 + 2.5 + 2.6 + 2.6 ] / 7 = 2.47 ≈ 2.5

Standard deviation: √  [ ∑ (x - mean)² / (n - 1) ] = 0.11


James’ data


Average = [2.4 + 3.0 + 3.3 + 2.2 + 2.9 + 3.8 + 2.9] / 7 = 2.56 ≈ 2.6


Standard deviation = 0.53

3) Conclusions:

1) The average of Abbie's data are closer to the accepted value 2.5g, so they are more accurate.

2) The standard deviation of Abbie's data is smaller than that of Jame's data, so the Abbie's data are more precise.
7 0
3 years ago
Read 2 more answers
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