Answer: Choice A) All points with an x-value of 3 are located in Quadrant I.
We can show it is false through the use of a counter example. For instance, the point (3, -5) is not in quadrant 1, but rather in quadrant 4.
We would need to say "all points with x value 3 and positive y value" to ensure the point is in quadrant 1.
Answer:
25-(116-1) = -89
(3-9)2 = -12
Step-by-step explanation:
25-(116-1)
<em>solve</em><em> </em><em>the</em><em> </em><em>ones </em><em>in</em><em> </em><em>the</em><em> </em><em>bracket</em><em> </em><em>first</em><em>.</em>
116-1 =115
<em>now</em><em> </em><em>solve</em><em> </em><em>the</em><em> </em><em>expr</em><em>ession</em>
25-(115)
25-115 = -89
(3-9)2
<em>brac</em><em>ket</em><em> </em><em>fi</em><em>rst</em>
3-9 = -6
<em>now</em><em> </em><em>solve</em><em> </em><em>the</em><em> expression</em>
(-6)2
-6×2 = -12
Answer:
The perimeter of the given semi-circle in terms of is
cm
Step-by-step explanation:
Given that the diameter of the semi-circle is 18cm
That is d=18cm
Therefore radius
Therefore radius r=9cm
To find the perimeter of the semi-circle :
perimeter of the semi-circle
cm (where r=9 cm )
cm
The perimeter of the given semi-circle in terms of is
cm