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zvonat [6]
3 years ago
5

Complete and balance the following redox equation using the set of smallest whole-number coefficients. Now sum the coefficients

of all species in the balanced equation. (Remember the coefficients that are equal to one.) BrO3-(aq) + Sb3+(aq) ? Br-(aq) + Sb5+(aq) (acid solution) The sum of the coefficients is ___.
Chemistry
1 answer:
EleoNora [17]3 years ago
4 0

Answer:

17

Explanation:

Oxidation reaction is defined as the chemical reaction in which an atom looses its electrons. The oxidation number of the atom gets increased during this reaction.

X\rightarrow X^{n+}+ne^-

Reduction reaction is defined as the chemical reaction in which an atom gains electrons. The oxidation number of the atom gets reduced during this reaction.

X^{n+}+ne^-\rightarrow X

For the given chemical reaction:

BrO_3^-(s)+Sb^{3+}(aq.)\rightarrow Br^-(aq.)+5Sb^{5+}(aq)

The half cell reactions for the above reaction follows:

Reduction half reaction:  BrO_3^-+6H^++6e^-\rightarrow Br^{-}+3H_2O

Oxidation half reaction:  Sb^{3+}\rightarrow Sb^{5+}+2e^-

Multiplying the Oxidation half reaction by 3 and we get that:-

3Sb^{3+}\rightarrow 3Sb^{5+}+6e^-

Adding the half reactions, we get that:-

BrO_3^-+6H^++3Sb^{3+}\rightarrow Br^{-}+3Sb^{5+}+3H_2O

<u>The sum of the coefficients is:- 1 + 6 + 3 + 1 + 3 + 3 = 17</u>

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Answer:

Cp_{liquid}=2.54\frac{J}{g\°C}

Explanation:

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In this case, since silver is initially hot as it cools down, the heat it loses is gained by the liquid, which can be thermodynamically represented by:

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That in terms of the heat capacities, masses and temperature changes turns out:

m_{Ag}Cp_{Ag}(T_2-T_{Ag})=-m_{liquid}Cp_{liquid}(T_2-T_{liquid})

Since no phase change is happening. Thus, solving for the heat capacity of the liquid we obtain:

Cp_{liquid}=\frac{m_{Ag}Cp_{Ag}(T_2-T_{Ag})}{-m_{liquid}(T_2-T_{liquid})} \\\\Cp_{liquid}=\frac{31.2g*0.237\frac{J}{g\°C}*(28.3-227.2)\°C}{185.8g*(28.3-24.4)\°C}\\ \\Cp_{liquid}=2.54\frac{J}{g\°C}

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