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Snowcat [4.5K]
2 years ago
9

True or false: Scientific models are always built to scale, and are fully functional representations of the product they are tes

ting.
Physics
1 answer:
vodka [1.7K]2 years ago
3 0

Answer:

False

Explanation:

Scientific models are not always built to scale and may not be fully accurate

You might be interested in
How is work defined in physics
Tcecarenko [31]

Explanation:

Work is the dot product of the force and displacement vectors.

W = F · d

In other words, it is the force times the parallel component of the distance.

W = F d cos θ, where θ is the angle between the force and distance.

3 0
3 years ago
What is the volume of a 1.2kg and displaced 1.0g/cm3
Zinaida [17]
Mass = 1.2 kg = 1200 grams.

Volume = mass/density = 1200 cm3.

Hope this helps!
4 0
3 years ago
A book sitting on a table is moved horizontally. Describe the
Akimi4 [234]

Frictional force and Applied force has same “magnitude” and “opposite” direction.  

Option: B  

<u>Explanation</u>:  

When a book is moved horizontally by applying “force” on the book, the frictional force is opposed to the book by the table. Here, this “frictional force” is opposing the book has the same force what we applied on the book but this frictional force and the applied force are opposite in direction. Always the “frictional force” is opposite to the “applied force” which stops the object to move. For example, if a force applied leftward to the object the frictional force is acted on the right side of the object.

When two objects are in contact they experience a "frictional force". This "frictional force" acts opposite to the force applied on to move the object.

Formula for "frictional force" is \mu\times N

Where, \mu is coefficient of friction and N is normal force.

3 0
3 years ago
Which of the following ways of writing 1000w is incorrect?
xenn [34]

Answer:

the third one is incorrect

Explanation:

10 x 10³= 10^1 x 10^3 = 10^4

8 0
3 years ago
A force of 14 lb is required to hold a spring stretched 4 in. beyond its natural length. How much work W is done in stretching i
enyata [817]

Answer:

W = 19.8 J

Explanation:

14 lb force is required to stretch the spring by 4 inch distance

So we have

F = 14 lbf

F = 6.35 \times 9.8 N

F = 62.3 N

stretch in the spring is given as

x = 4 in = 0.1016 m

now we will have

F = kx

62.3 = k(0.1016)

k = 613.125 N/m

Now we need to find the work to stretch it by x = 10 in = 0.254 m

so we have

W = \frac{1}{2}kx^2

W = \frac{1}{2}(613.125)(0.254)^2

W = 19.8 J

7 0
3 years ago
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