1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
mars1129 [50]
4 years ago
13

Compared to the earth would the sun appear to move more quickly across Mercury’s sky or more slowly? Why?

Physics
1 answer:
denis23 [38]4 years ago
7 0

Faster because of the distance mercury in to the sun

You might be interested in
What is fundamental questioning came now<br>cfy_tuhq_wjt​
Nadya [2.5K]

Answer:

juz taking points nvm no sry for u cos u too wasted point

8 0
3 years ago
True or false? All waves need a medium in order to travel
Art [367]
That's false.  Mechanical waves (like sound and ocean waves) do
need a medium to travel in, but electromagnetic waves (like radio
and light) don't.
4 0
3 years ago
Read 2 more answers
Which terrestrial planet exhibits retrograde rotation?.
Sati [7]

Answer:

Planets that are farther from the sun than the earth (all but Mercury and Venus) will exhibit retrograde motion.

If the position of the planet is observed relative to the background stars, the planet will appear to move backward relative to the stars when the earth is moving in an Eastward direction faster than the planet, and the planet appears to move backwards relative to the stars

(The planet will be on the side of the earth that is opposite that of the sun)

3 0
2 years ago
What is the outcome of a star that runs out of hydrogen?
AlexFokin [52]
These stars fuse helium into carbon just like the sun.
3 0
3 years ago
Read 2 more answers
An accepted value for the acceleration due to gravity is 9.801 m/s2. In an experiment with pendulums, you calculate that the val
Fed [463]

g Generally the accepted value of acceleration due to gravity is 9.801 m/s^2

as per the question the acceleration due to gravity is found to be 9.42m/s^2 in an experiment performed.

the difference between the ideal and observed value is 0.381.

hence the error is -\frac{0.381}{9.801} *100

                                                            =3.88735 percent

the error is not so high,so it can be  accepted.

now we have to know why this occurs-the equation of time period of the simple pendulum is give as-T=2\pi\sqrt[2]{l/g}

                                                      g=4\pi^2\frac{l}{T^2}

As the experiment is done under air resistance,so it will affect to the time period.hence the time period will be more which in turn decreases the value of g.

if this experiment is done in a environment of zero air resistance,we will get the value of g which must be approximately equal to 9.801  m/s^2

5 0
4 years ago
Other questions:
  • A lawyer drives from her​ home, located 1 mile east and 8 miles north of the town​ courthouse, to her​ office, located 4 miles w
    8·1 answer
  • Types of energy transferred from mechanical waves
    13·1 answer
  • A man dropped a dime in a wishing well , he heard it 5 sec later ..Find distance traveled if moving at 10 m/s 2
    15·1 answer
  • A ball on the end of a rope is moving in a vertical circle near the surface of the earth. Point A is at the top of the circle; C
    10·1 answer
  • Please help i need an explanation
    5·1 answer
  • Two runners start simultaneously from the same point on a circular 200-m track and run in the same direction. One runs at a cons
    6·1 answer
  • A 1.80-kg object is attached to a spring and placed on frictionless, horizontal surface. A horizontal force of 15.0 N is require
    10·2 answers
  • What does the temperature of the gas between galaxies in galaxy clusters tell us about the mass of the cluster
    6·1 answer
  • Describe how wavelength is defined for transverse waves and for longitudinal waves.
    10·1 answer
  • Q.01 When charging a secondary cell, energy is stored within a dielectric material using an electric field. True or False
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!