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tankabanditka [31]
1 year ago
14

Using the thermodynamic information in the aleks data tab, calculate the standard reaction free energy of the following chemical

reaction: 2ch3oh 3o2=2co2 4h2o
Physics
1 answer:
Ganezh [65]1 year ago
5 0

The standard reaction free energy is the total energy change of a chemical reaction that occurs at standard conditions. The standard reaction free energy is calculated by subtracting the heat of formation from the enthalpy of formation.

standard reaction free energy = -Hf-Hf

The standard Gibbs free energy, on the other hand, is the total of the enthalpy and the entropy. The Gibbs free energy is a thermodynamic potential that depends on the enthalpy and entropy of a system. The change in the Gibbs free energy is equal to ΔG=ΔH-TΔS.

The enthalpy of formation is a measure of how much heat must be put in to break down a compound into its constituent elements. The heat of formation is an estimate of how much heat will be released when the same compound is formed from its constituent elements.

<h3>How is the standard reaction free energy calculated?</h3>

The standard reaction free energy is the change in Gibbs free energy, which is the enthalpy minus the entropy. This can be calculated by using E=ΔH-TΔS. The ΔG (298K,1 atm) for a reaction with a standard state change from 1 atm to 298 K (the most common atmospheric pressure and temperature), and 1 mol of reactants is equal to 0. The ΔG(298K,1 atm) for a reaction with standard state changes from 1 atm to 298 K and from 298 K to 1 atm are equal to 0.

The standard reaction free energy can be calculated by using the following equation:

E=ΔH-TΔS, where E is the standard free energy of the reaction.

To learn more about standard reaction free energy, visit:

brainly.com/question/13242644

SPJ4

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Answer:a. Magnetic dipole moment is 0.3412Am²

b. Torque is zero(0)N.m

Explanation: The magnetic dipole moment U is given as the product of the number of turns n times the current I times the area A

That is,

U = n*I*A

But Area A is given as pi*radius² since it is a circular coil

Radius given is 5cm converting to meter we divide by 100 so we have our radius to be 0.05m. So area A is

A = 3.142*(0.05)² =7.86*EXP {-3} m²

Current I is 2 A

Number of turns is 20

So magnetic dipole moment U is

U = 20*2*7.86*EXP {-3}=0.3142A.m²

b. Torque is given as the cross product of the magnetic field B and magnetic dipole moment U

Torque = B x U =B*U*Sine(theta)

But since the magnetic field is directed parallel to the plane of the coil from the question, it means that the angle between them is zero and sine zero is equals 0(zero) if you substitute that into the formula for torque you will find out that your torque would equals zero(0)N.m

7 0
3 years ago
If the time of impact in a collision is extended by 3 times, by hour much is
vodomira [7]

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The force of the impact would be smaller

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If the force is small then the time would be big (250N of Force = 50 seconds)

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F = 82 / 1.5 = 54.67 N

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How was the gravitational constant G first determined
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