Using the thermodynamic information in the aleks data tab, calculate the standard reaction free energy of the following chemical
1 answer:
The standard reaction free energy is the total energy change of a chemical reaction that occurs at standard conditions. The standard reaction free energy is calculated by subtracting the heat of formation from the enthalpy of formation.
standard reaction free energy = -Hf-Hf
The standard Gibbs free energy, on the other hand, is the total of the enthalpy and the entropy. The Gibbs free energy is a thermodynamic potential that depends on the enthalpy and entropy of a system. The change in the Gibbs free energy is equal to ΔG=ΔH-TΔS.
The enthalpy of formation is a measure of how much heat must be put in to break down a compound into its constituent elements. The heat of formation is an estimate of how much heat will be released when the same compound is formed from its constituent elements.
<h3>How is the standard reaction free energy calculated?</h3>The standard reaction free energy is the change in Gibbs free energy, which is the enthalpy minus the entropy. This can be calculated by using E=ΔH-TΔS. The ΔG for a reaction with a standard state change from
atm to
K (the most common atmospheric pressure and temperature), and 1 mol of reactants is equal to 0. The ΔG
for a reaction with standard state changes from 1 atm to 298 K and from
to
atm are equal to
.
The standard reaction free energy can be calculated by using the following equation:
E=ΔH-TΔS, where E is the standard free energy of the reaction.
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Answer:
78.4 KN/m
Explanation:
Given
mass of person 'm' =80 kg
car dips about i.e spring stretched 'x'= 1 cm => 0.01m
acceleration due to gravity 'g'= 9.8 m/s^2
as we know that,in order to find approximate spring constant we use Hooke's Law i.e F=kx
where,
F = the force needed
x= distance the spring is stretched or compressed beyond its natural length
k= constant of proportionality called the spring constant.
F=kx ---> (since f=mg)
mg=kx
k=(mg)/x
k=(80 x 9.8)/ 0.01
k=78.4x
k=78.4 KN/m
Answer:
F = -4567.40 N
Explanation:
Given that,
The power developed by the engine, P = 196 hp
1 hp = 746 W
196 hp = 146157 W
Speed of the car, v = 32 m/s
Let F is the total friction force acting on the car. The product of force and velocity is called the power developed by the engine. It is given by :
F = -4567.40 N
So, the total frictional force acting on the car is 4567.40 N. Hence, this is the required solution.
Actually Welcome to the concept of Efficiency.
Here we can see that, the Input work is given as 2.2 x 10^7 J and the efficiency is given as 22%
The efficiency is => 22% => 22/100.
so we get as,
E = W(output) /W(input)
hence, W(output) = E x W(input)
so we get as,
W(output) = (22/100) x 2.2 x 10^7
=> W(output) = 0.22 x 2.2 x 10^7 => 0.484 x 10^7
hence, W(output) = 4.84 x 10^6 J
The useful work done on the mass is 4.84 x 10^6 J