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tankabanditka [31]
2 years ago
14

Using the thermodynamic information in the aleks data tab, calculate the standard reaction free energy of the following chemical

reaction: 2ch3oh 3o2=2co2 4h2o
Physics
1 answer:
Ganezh [65]2 years ago
5 0

The standard reaction free energy is the total energy change of a chemical reaction that occurs at standard conditions. The standard reaction free energy is calculated by subtracting the heat of formation from the enthalpy of formation.

standard reaction free energy = -Hf-Hf

The standard Gibbs free energy, on the other hand, is the total of the enthalpy and the entropy. The Gibbs free energy is a thermodynamic potential that depends on the enthalpy and entropy of a system. The change in the Gibbs free energy is equal to ΔG=ΔH-TΔS.

The enthalpy of formation is a measure of how much heat must be put in to break down a compound into its constituent elements. The heat of formation is an estimate of how much heat will be released when the same compound is formed from its constituent elements.

<h3>How is the standard reaction free energy calculated?</h3>

The standard reaction free energy is the change in Gibbs free energy, which is the enthalpy minus the entropy. This can be calculated by using E=ΔH-TΔS. The ΔG (298K,1 atm) for a reaction with a standard state change from 1 atm to 298 K (the most common atmospheric pressure and temperature), and 1 mol of reactants is equal to 0. The ΔG(298K,1 atm) for a reaction with standard state changes from 1 atm to 298 K and from 298 K to 1 atm are equal to 0.

The standard reaction free energy can be calculated by using the following equation:

E=ΔH-TΔS, where E is the standard free energy of the reaction.

To learn more about standard reaction free energy, visit:

brainly.com/question/13242644

SPJ4

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Answer:

X = 2.882×10⁵ N,

Y =  1.43×10⁴ N

Explanation:

From the diagram attached,

Let the reaction from the two support be X and Y.

According to the condition of equilibrium

Sum of upward force = sum of downward force.

X+Y = 5.25×10⁴+2.5×10⁵

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Also,

Sum of clockwise moment = sum of anticlockwise moment.

Take the moment about support A

(10.2×5.25×10⁴)+(18.25×2.56×10⁵) = 36.5×Y

52.075×10⁴ = 36.5Y

Y =52.075×10⁴/36.5

Y = 1.43×10⁴ N.

Substituting the value of Y into equation 1

X+ 1.43×10⁴ = 3.025×10⁵

X = 3.025×10⁵-1.43×10⁴

X = 2.882×10⁵ N.

Hence the force provided by each supports are

X = 2.882×10⁵ N, and Y =  1.43×10⁴ N

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It is given that that initial volume of gas is 20 cubic inches.

The initial pressure is given as 5 psi.

The final pressure is given as 10 psi

We are asked to calculate the final volume.

Let initial and final volume of gas is denoted as v_{1} \ and\ v_{2}

Let the initial and final pressure of gas is denoted as p_{1} \ and\ p_{2}

As per the question the temperature of a gas is constant.

From Boyle's law we know that pressure of a given mass of a gas is inversely proportional to the applied volume at constant temperature.

Hence mathematically

                                p\ \alpha\ \frac{1}{v}

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