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tankabanditka [31]
1 year ago
14

Using the thermodynamic information in the aleks data tab, calculate the standard reaction free energy of the following chemical

reaction: 2ch3oh 3o2=2co2 4h2o
Physics
1 answer:
Ganezh [65]1 year ago
5 0

The standard reaction free energy is the total energy change of a chemical reaction that occurs at standard conditions. The standard reaction free energy is calculated by subtracting the heat of formation from the enthalpy of formation.

standard reaction free energy = -Hf-Hf

The standard Gibbs free energy, on the other hand, is the total of the enthalpy and the entropy. The Gibbs free energy is a thermodynamic potential that depends on the enthalpy and entropy of a system. The change in the Gibbs free energy is equal to ΔG=ΔH-TΔS.

The enthalpy of formation is a measure of how much heat must be put in to break down a compound into its constituent elements. The heat of formation is an estimate of how much heat will be released when the same compound is formed from its constituent elements.

<h3>How is the standard reaction free energy calculated?</h3>

The standard reaction free energy is the change in Gibbs free energy, which is the enthalpy minus the entropy. This can be calculated by using E=ΔH-TΔS. The ΔG (298K,1 atm) for a reaction with a standard state change from 1 atm to 298 K (the most common atmospheric pressure and temperature), and 1 mol of reactants is equal to 0. The ΔG(298K,1 atm) for a reaction with standard state changes from 1 atm to 298 K and from 298 K to 1 atm are equal to 0.

The standard reaction free energy can be calculated by using the following equation:

E=ΔH-TΔS, where E is the standard free energy of the reaction.

To learn more about standard reaction free energy, visit:

brainly.com/question/13242644

SPJ4

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Answer:

Smallest drop: Water

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Explanation:

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\Delta T=-\frac{Q}{cm} =\frac{Q}{4186*4.0}

\Delta T=-\frac{Q}{16744}

Sample B:

\Delta T=-\frac{Q}{cm} =\frac{Q}{2700*2.0}

\Delta T=-\frac{Q}{5400}

Sample C:

\Delta T=-\frac{Q}{cm} =\frac{Q}{1050*9.0}

\Delta T=-\frac{Q}{9450}

Note that the numbers 16744, 5400, 9450 are in the denominator of the expression -\frac{Q}{cm} that gives the drop on temperature. so, if Q is the same for the three samples the smallest denominator gives the largest drop and vice versa.

So, the smallest drop is Sample A and the largest is Sample C.

(Important: The minus sign of \Delta T implies the temperature is dropping)

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3 years ago
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Answer:

Explanation:

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Also, since you and Budda are a distance of 4m to each other, then the length to which both meet buddy will be:

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∴

We can find the center of mass of the system by using the formula:

X_{CM} = \dfrac{m_1x_1+m_2x_2+m_3x_3}{m_1+m_2+m_3} \\ \\ X_{CM} = \dfrac{(80 \times 2)+(120\times4)+(60\times2)}{80+120+60} \\ \\ X_{CM} = \dfrac{160+480+120}{260} \\ \\ \mathbf{X_{CM} = 2.923}

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6 0
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3 years ago
What is the answer to this definition ?
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