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tankabanditka [31]
1 year ago
14

Using the thermodynamic information in the aleks data tab, calculate the standard reaction free energy of the following chemical

reaction: 2ch3oh 3o2=2co2 4h2o
Physics
1 answer:
Ganezh [65]1 year ago
5 0

The standard reaction free energy is the total energy change of a chemical reaction that occurs at standard conditions. The standard reaction free energy is calculated by subtracting the heat of formation from the enthalpy of formation.

standard reaction free energy = -Hf-Hf

The standard Gibbs free energy, on the other hand, is the total of the enthalpy and the entropy. The Gibbs free energy is a thermodynamic potential that depends on the enthalpy and entropy of a system. The change in the Gibbs free energy is equal to ΔG=ΔH-TΔS.

The enthalpy of formation is a measure of how much heat must be put in to break down a compound into its constituent elements. The heat of formation is an estimate of how much heat will be released when the same compound is formed from its constituent elements.

<h3>How is the standard reaction free energy calculated?</h3>

The standard reaction free energy is the change in Gibbs free energy, which is the enthalpy minus the entropy. This can be calculated by using E=ΔH-TΔS. The ΔG (298K,1 atm) for a reaction with a standard state change from 1 atm to 298 K (the most common atmospheric pressure and temperature), and 1 mol of reactants is equal to 0. The ΔG(298K,1 atm) for a reaction with standard state changes from 1 atm to 298 K and from 298 K to 1 atm are equal to 0.

The standard reaction free energy can be calculated by using the following equation:

E=ΔH-TΔS, where E is the standard free energy of the reaction.

To learn more about standard reaction free energy, visit:

brainly.com/question/13242644

SPJ4

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A 174 pound Jimmy Cheek is riding on a 54 ft diameter Ferris Wheel. The normal force on Jimmy Cheek is 146 pounds when Jimmy is
Veronika [31]

To solve this problem we will apply the concepts related to the balance of Forces, the centripetal Force and Newton's second law.

I will also attach a free body diagram that allows a better understanding of the problem.

For there to be a balance between weight and normal strength, these two must be equivalent to the centripetal Force, therefore

F_c = W-N

m\omega^2r = W-N

Here,

m = Net mass

\omega= Angular velocity

r = Radius

W = Weight

N = Normal Force

m\omega^2r = 174-146

The net mass is equivalent to

F = mg \rightarrow m = \frac{F}{g}

Then,

m = \frac{174lb}{32.17ft/s^2}

Replacing we have then,

(\frac{174lb}{32.17ft/s^2})\omega^2 (54ft) =174lb-146lb

Solving to find the angular velocity we have,

\omega = 0.309rad/s

Therefore the angular velocity is 0.309rad/s

6 0
3 years ago
Calculate the kinetic energy of a motorcycle of mass 60kg travelling at a velocity of 40km/h​
ELEN [110]

Answer:

1848.15J

Explanation:

KE =1/2 mv^2

Mass = 60kg, velocity =40km/h =11.11m/s

Hence

KE =30 x(11.1)^2 /2 = 1848.15J

5 0
3 years ago
A boy on board a cruise ship drops a 30. 0 gm marble into the ocean. If the resistive force proportionality constant is 0. 500 k
svlad2 [7]

The terminal speed of the marble is 0.588 m/s.

<h3>Calculation:</h3>

We know that,

F = mg                                                   ......(1)

where,

F = force

m = mass

g = acceleration due to gravity

Also,

v = F/k                                                       ......(2)

where,

v = terminal speed

k = proportionality constant

Substituting the value of F from equation (1) in equation (2)

v = mg/k                                                         .......(3)

Given,

m = 30 g = 0.030 kg

k = 0.500 kg/s

g = 9.8 m/s²

To find,

v =?

Put the values in equation (3)

v = mg/k              

v = 0.03(9.8)/ 0.500

  = 0.294/0.500

  = 0.588 m/s

​

Hence, the terminal speed of the marble is 0.588 m/s.

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5 0
2 years ago
Read 2 more answers
A standard 1 kilogram weight is a cylinder 40.0 mm in height and 53.5 mm in diameter. What is the density of the material?
jek_recluse [69]

Answer:

1.15*10^-5 kg/m^3

Explanation:

Given data

mass= 1kg

hieght= 40 mm

diameter= 52.5mm

radius= 53.5/2= 26.25mm

The volume of the cylinder

V=πr^2h

V=3.142*26.25^2*40

V=3.142*689.0625*40

V=86601.375 mm^3

Density= mass/volume

Density= 1/86601.375

Density=0.00001154716

Density= 1.15*10^-5 kg/m^3

Hence the density is  1.15*10^-5 kg/m^3

8 0
3 years ago
Two clay balls collide head-on in a perfectly inelastic collision. The first ball has a mass of 0.500 kg and an initial velocity
mrs_skeptik [129]

Answer:

v'=1.667\ m.s^{-1}  in the direction of the first body

Explanation:

Given:

  • mass of the first ball, m_1=0.5\ kg
  • velocity of the first ball, v_1=4\ m.s^{-1}
  • mass of the second ball, m_2=0.25\ kg
  • velocity of the second ball, v_2=3\ m.s^{-1}

<u>Now for the head-on inelastic collision:</u>

m_1.v_1-m_2.v_2=(m_1+m_2)v'

(since the bodies combine after an inelastic collision.)

0.5\times 4-0.25\times 3=(0.5+0.25)\times v'

v'=1.667\ m.s^{-1} in the direction of the first body. (Since the net result is positive as assumed in the equation for the first body)

4 0
3 years ago
Read 2 more answers
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