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choli [55]
3 years ago
12

Which statement about the properties of matter is true? *25*

Physics
1 answer:
mojhsa [17]3 years ago
3 0

Answer:

A possible answer would be that chemical properties depend on phisical properties if and if only the phisical properties depend on the chemical ones ( see the laws of thermodinamics)

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When you ride your bike around a corner at 10 m/s, you are accelerating?
WINSTONCH [101]

When you ride your bike around a corner at 10 m/s, you are accelerating. Acceleration is caused by any forces. Sliding friction keeps you in the seat when a car goes around a corner. If you throw a ball into the air, Earth exerts a force on the ball.

5 0
3 years ago
Read 2 more answers
Blocks A (mass 2.00 kg) and B (mass 6.00 kg) move on a frictionless, horizontal surface. Initially, block B is at rest and block
Oksana_A [137]

Answer:

av=0.333m/s, U=3.3466J

b.

v_{A2}=-1.333m/s,\\ v_{B2}=0.667m/s

Explanation:

a. let m_A be the mass of block A, andm_B=10.0kg be the mass of block B. The initial velocity of A,\rightarrow v_A_1=2.0m/s

-The initial momentum =Final momentum since there's no external net forces.

pA_1+pB_1=pA_2+pB_2\\\\P=mv\\\\\therefore m_Av_A_1+m_Bv_B_1=m_Av_{A2}+m_Bv_{B2}

Relative velocity before and after collision have the same magnitude but opposite direction (for elastic collisions):

v_A_1-v_B_1=v_{B2}-v_{A2}

-Applying the conservation of momentum. The blocks have the same velocity after collision:

v_{B2}=v_{A2}=v_2\\\\2\times 2+10\times 0=2v_2+10v_2\\\\v_2=0.3333m/s

#Total Mechanical energy before and after the elastic collision is equal:

K_1+U_{el,1}=K_2+U_{el,2}\\\\#Springs \ in \ equilibrium \ before \ collision\\\\U_{el,2}=K_1-K_2=0.5m_Av_A_1^2-0.5(m_A+m_B)v_2^2\\\\U_{el,2}=0.5\times 2\times 2^2-0.5(2+10)(0.333)^2\\\\U_{el,2}=3.3466J

Hence, the maxumim energy stored is U=3.3466J, and the velocity=0.333m/s

b. Taking the end collision:

From a above, m_A=2.0kg, m_B=10kg, v_A=2.0,v_B_1=0

We plug these values in the equation:

m_Av_A_1+m_Bv_B_1=m_Av_{A2}+m_Bv_{B2}

2\times2+10\times0=2v_A_2+10v_B_2\\\\2=v_A_2+5v_B_2\\\\#Eqtn 2:\\v_A_1-v_B_1=v_{B2}-v_{A2}\\\\2-0=v_{B2}-v_{A2}\\\\2=v_{B2}-v_{A2}\\\\#Solve \ to \ eliminate \ v_{A2}\\\\6v_{B2}=2.0\\\\v_{B2}==0.667m/s\\\\#Substitute \ to \ get \ v_{A2}\\\\v_{A2}=\frac{4}{6}-2=1.333m/s

7 0
4 years ago
When a person holds an object, it has potential energy. How will the potential energy change if the person lifts the object abov
anygoal [31]

Answer:

While In an <em><u>ideal/isolated</u></em> system, as long as the object is not in motion, its potential energy will be the same.

However, <u>potential energy is relative</u>. On Earth, usually, it is measured with respect to gravity. <u>The higher the object, the greater the potential gravitational energy</u>. It's all relative. For the sake of this question, I would assume that potential energy increases.

Explanation:

While kinetic energy depends upon speed, potential energy is always relative to some arbitrary reference point.

Source https://www.physicsforums.com/threads/potential-energy-kinetic-energy.11481/

6 0
4 years ago
Read 2 more answers
Oil explorers set off explosives to make loud sounds, then listen for the echoes from underground oil deposits. Geologists suspe
Elenna [48]

Answer:

dg= 942m

Explanation:

given the depth of the granite Us dg = 500m

time between the explosion t = 0.99s

the speed of sound in granite is Vg = 6000m/s

First of all calculate the time it takes the sound waves to travel down through the lake

Vw = dw/t1

t1 = dw/Vw

t1 = 500/1480

t1 = 0.338s.

Let dg be the depth of the granite basin, so the time it takes for the sound to travel down through the granite is t2 = dg/6000m/s......equation(1)

So the total time it takes to travel down to the oil surface will be

t1/2 = t1 + t2

t1/2=  0.338 + dg/6000.

since the reflection on the oil does not change the speed of sound, the sound will take travelling upto the surface the same time it takes to reach the oil

so; t = 2 t1/2

t1/2 = t/2 = 0.99s/2 = 0.495

Now insert into the values of t1/2 into the equation (1) and solve for dg;

we get 0.495 = 0.338 + dg/6000

dg = (0.495 - 0.338) x 6000

dg = 942m.

3 0
3 years ago
Read 2 more answers
A charged particle decelerates as it moves from location a to location b. if va = 160 v and vb = 100 v, what is the sign of the
skelet666 [1.2K]

The sign of the charged particle is positively charged.

<h3>What is potential difference?</h3>
  • When a single charge is transported in an electric field, work is done by the potential difference (also known as electrical potential).
  • There is potential energy stored in this charge that could flow when work is done on it.
  • Voltage is the possibility of a single charge flowing. The need to flow increases with voltage.
  • Here, voltage can be the potential differences.

The potential difference between the 2 points determines the movement of that particle. An electron moves from lower to higher potential which is negatively charged, and a positively charged particle moves  from higher to lower potential.

Now, since the particle is moving from a point A having 160 v potential to point B having 100 v potential that is it is moving from higher potential to a lower potential therefore the particle will be a positively charged one.

Learn more about potential difference,

brainly.com/question/23716417

#SPJ1

3 0
2 years ago
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