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ikadub [295]
2 years ago
5

If 0.850 L of a 5.00-Msolution of copper(II) nitrate, Cu(NO3)2, is diluted to a volume of 1.80 L by the addition of water, what

is the molarity of the diluted solution
Chemistry
1 answer:
7nadin3 [17]2 years ago
8 0

The molarity of the diluted solution is 2.36M

M₁L₁ = M₂L₂

M₂ = M₁L₁/L₂

M₂ = (5.00 M x 0.850 L)/ 1.80 L

M₂ = 2.36 M Cu(NO₃)₂

<h3>Molarity </h3>

The volume of a material present in a given volume of solution is known as its molarity (M). The number of moles of a solute in a liter of solution is referred to as molarity. The term "molarity" can also refer to a solution's molar concentration. Molarity (M) is the number of moles of a solute per liter of a solution, also referred to as the molar concentration of a solution. The symbols mol/L or, more commonly, M can be used to represent molarity. The word "molar concentration" refers to the amount of a substance per unit volume of solution and is used to describe the concentration of a chemical species, specifically a solute, in a solution. Molarity, amount, and substance concentration are other names for this term.

Learn more about molarity here:

brainly.com/question/8732513

#SPJ4

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Answer:

The mass of P₄O₁₀ (s) formed is 471.03 g

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This is the ballanced equation.

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Moles PH₃ = 225 g / 33.9 g/m

Moles PH₃ = 6.63 moles

So the rule of three, will be:

If 4 moles of PH₃ generate 1 mol  P₄O₁₀

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Moles . Molar mass = mass

Molar mass  P₄O₁₀  = 283.88 g/m

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3 0
3 years ago
Laws of conservation of mass/pleases help
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27g + 33g = 60g

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Explanation:

According to Valence Shell Electron Pair Repulsion Theory, the shape of a molecule depends on the number of electron pairs on the valence shell of the central atom in the molecule.

For all the compounds listed, the central atom has four points of electron density. This correspond to a tetrahedra electron pair geometry. The presence of lone pairs on the central atom of OF2,NF3 and H2S accounts for the departure of the observed molecular geometry from the geometry and idealized bond angle predicted on the basis of the VSEPR theory.

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The value of ΔH° for the reaction below is -126 kJ. The amount of heat that is released by the reaction of 25.0 g of Na2O2 with
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20.2 kJ

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